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dangina [55]
3 years ago
11

The shape of a protein molecule resembles _____.

Chemistry
2 answers:
emmainna [20.7K]3 years ago
8 0

The shape of a protein molecule resembles BEADS ON A STRING.

Proteins are macro molecules that are formed from amino acids. There are different types of amino acids, thus, different amino acids combine together to form different types of protein. This means that, proteins are formed from sequences of amino acids; they are long chains of different amino acids, that is why, they are likened to beads on string.

The structures of proteins are in three dimensions, they are primary, secondary and tertiary structures. The primary structure refers to the sequence of the amino acids in a protein. The amino acids in the primary structure are linked together by peptide bonds.

White raven [17]3 years ago
4 0
<span>the shape of a protein molecule resembles : beads on a string a protein. Molecule is made from a long chain of amino acids whichi linked through covalent peptide bond that contains each unique sequence of the amino acids, forming a long, chain-like molecules</span>
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If a piece of cadmium with a mass of 37.60 g and a temperature of 100.0 oC is dropped into 25.00 cc of water at 23.0 oC, what wi
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Answer:

T_{eq}=28.9\°C

Explanation:

Hello!

In this case, since it is observed that hot cadmium is placed in cold water, we can infer that the heat released due to the cooling of cadmium is gained by the water and therefore we can write:

Q_{Cd}+Q_{W}=0

Thus, we insert mass, specific heat and temperatures to obtain:

m_{Cd}C_{Cd}(T_{eq}-T_{Cd})+m_{W}C_{W}(T_{eq}-T_{W})=0

In such a way, since the specific heat of cadmium and water are respectively 0.232 and 4.184 J/(g °C), we can solve for the equilibrium temperature (the final one) as shown below:

T_{eq}=\frac{m_{Cd}C_{Cd}T_{Cd}+m_{W}C_{W}T_{W}}{m_{Cd}C_{Cd}+m_{W}C_{W}}

Now, we plug in to obtain:

T_{eq}=\frac{37.60g*0.232\frac{J}{g\°C}*100.00\°C+25.00g*4.184\frac{J}{g\°C}*23.0\°C}{37.60g*0.232\frac{J}{g\°C}+25.00g*4.184\frac{J}{g\°C}}\\\\T_{eq}=28.9\°C

NOTE: since the density of water is 1g/cc, we infer that 25.00 cc equals 25.00 g.

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