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dangina [55]
3 years ago
11

The shape of a protein molecule resembles _____.

Chemistry
2 answers:
emmainna [20.7K]3 years ago
8 0

The shape of a protein molecule resembles BEADS ON A STRING.

Proteins are macro molecules that are formed from amino acids. There are different types of amino acids, thus, different amino acids combine together to form different types of protein. This means that, proteins are formed from sequences of amino acids; they are long chains of different amino acids, that is why, they are likened to beads on string.

The structures of proteins are in three dimensions, they are primary, secondary and tertiary structures. The primary structure refers to the sequence of the amino acids in a protein. The amino acids in the primary structure are linked together by peptide bonds.

White raven [17]3 years ago
4 0
<span>the shape of a protein molecule resembles : beads on a string a protein. Molecule is made from a long chain of amino acids whichi linked through covalent peptide bond that contains each unique sequence of the amino acids, forming a long, chain-like molecules</span>
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Sonbull [250]

Answer:

the reactor was overheating

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3 years ago
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Serhud [2]
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4 0
4 years ago
What is the approximate temperature of 1.4 moles of a gas with a pressure of 3.25 atmospheres in a 4.738-liter container
attashe74 [19]

Answer:

134K

Explanation:

Using the ideal gas law equation;

PV = nRT

Where;

P = pressure (atm)

V = volume (Litres)

n = number of moles (mol)

R = gas constant (0.0821 Latm/Kmol)

T = temperature (K)

Based on the information provided, n = 1.4moles, P = 3.25atm, V = 4.738L, T = ?

3.25 × 4.738 = 1.4 × 0.0821 × T

15.3985 = 0.11494T

T = 15.3985/0.11494

T = 133.969

Approximately;

T = 134K

3 0
3 years ago
2. A 10.0 g ice cube, initially at 0.0ºC, is melted in 100.0 g of water that was initially 20.0ºC. After the ice has melted, the
arlik [135]

Answer:

The heat lost  by the water  Q_{water}  = 3.8 KJ

The heat gain by ice  Q_{ice} = 228.76 J

The heat required to melt the ice Q_{melt} = 3340 J

Explanation:

Mass of ice cube m_{ice} = 10 gm

Initial temperature of ice cube T_{ice} = 0 °c

Mass of water m_{water} = 100 gm

Initial temperature of water T_{w} = 20 °c

Final temperature of mixture T_{f} = 10.93 °c

(a). Total heat lost by the water Q_{water}  =  m_{water} C_{w} ( T_{f} - T_{w} )

⇒ Q_{water}  = 100 × 4.184 (20 - 10.93)

⇒ Q_{water}  = 3.8 KJ

This is the heat lost  by the water.

(b). Heat gained by the ice cube Q_{ice} = m_{ice} C_{ice} (T_{f} - T_{ice}  )

⇒ Q_{ice} = 10 × 2.093 × ( 10.93 - 0)

⇒ Q_{ice} = 228.76 J

This is the heat gain by ice.

(C). Heat required to melt the ice Q_{melt} = m_{ice} × Latent Heat

⇒ Q_{melt} = 10 × 334

⇒ Q_{melt} = 3340 J

This is the heat required to melt the ice.

7 0
3 years ago
Physical and chemical properties of metals and non metals
densk [106]

Answer:

Metals Good conductors of electricity good conductors of heat

High density

Malleable and ductile

Non-metals

Poor conductors of electricity

Poor conductors of heat

Low density

brittle

8 0
4 years ago
Read 2 more answers
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