Answer:
A
Step-by-step explanation:
line 1 is perpendicular to line 2 because of 90°.
line 2 is parallel to line 3 because of corresponding angles
I think that it might be "c" but I am not sure but hey it is worth a shot sorry if I am wrong!
Answer:
See explanation
Step-by-step explanation:
<u>Question 1. </u>Write two-column proof.
Statement Reason
1.
Given
2.
Distributive Property of Equality
3.
Subtraction Property of Equality
4.
Division Property of Equality
<u>Question 2.</u>
Statement Reason
1.
Given
2.
Given
3.
Angle Addition Postulate
4.
Substitution Property of Equality
5.
is a right angle Definition of a right angle
6.
is a right triangle Definition of a right triangle
<u>Question 3:</u>
Statement Reason
1.
and
are supplementary Given
2.
Definition of supplementary angles
3.
Given
4.
Substitution Property of Equality
5.
Subtraction Property of Equality
Answer:
Our inequality is 8 < x < 10, where x is our number.
Since the problem doesn't specify whether the number x is an integer or not, we can assume that x can be either a decimal or a whole number. That means that we want any decimal number or whole number between 8 and 10. The only whole number is 9, but there are infinitely many decimal solutions. For example, we could have 8.001, 8.0001, 8.00001, etc.
Thus the answer is D.
Hope this helps!
Step-by-step explanation:
Answer:
4 students
Step-by-step explanation:
Although I am not sure if I am completely correct. I’ll try my best.
<u>We know:</u>
The numbers 0-12 on the frequency table is the number of windows.
The numbers on the bottom is the amount of students.
-
<u>What we can see:</u>
As we can see..
- the 0-4 section in the table shows that only 0-4 students have 9 windows.
- The 5-9 sections shows that only 5-9 students have 10 windows.
- The 10-14 sections shows that 10-14 students have 0 windows.
- The 15-19 sections shows that 15-19 students have 4 windows.
- The 20-24 sections shows that 20-24 students have 2 windows.
-
<u>Calculations:</u>
Since the number of students that have the amount of windows less than 10 is 4 (0-4 section) and 0 (10-14 section)
Add.
4+0
= 4
Therefore, 4 students have less than 10 windows.
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