Answer:
Small flags = 108
large flags= 47
Step-by-step explanation:
Step one:
given
let the number of small lag be x
and big flags be y
so
3.5x+6.5y= 683.5----------1
x+y=155------------------------2
Step two:
from eqn 2 x= 155-y
put x= 155-y in eqn 1
3.5(155-y)+6.5y= 683.5
542.5-3.5y+6.5y=683.5
collect like terms
3y=141
divide by 3
y= 141/3
y=47
Step three:
put y= 47 in eqn 2
x+47=155
x= 155-47
x=108
Answer:
D. All of the above.
Step-by-step explanation: Please brainliest if correct!
Solution
2014 - 1969 = 45
45 x 0.2633 = 11.8485 = 12
Final Answer:
C) 26.33%
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Answer:
x=6
Step-by-step explanation: