1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
stepan [7]
3 years ago
10

4. The diameters of bolts produced by a certain machine are normally distributed with a mean of 0.35 inches and a standard devia

tion of 0.03 inches. What percentage of bolts will have a diameter greater than 0.37 inches? Round your answer to two decimal places.
Physics
1 answer:
slamgirl [31]3 years ago
3 0

Answer:

25.25%

Explanation:

Mean diameter (μ) = 0.35 inches

Standard deviation (σ) = 0.03 inches

For any given diameter, X, the z-score is given by:

z=\frac{X-\mu}{\sigma}

For X= 0.37 inches:

z=\frac{0.37-0.35}{0.03}\\z=0.6667

A z-score of 0.6667 is equivalent to the 74.75-th percentile of a normal distribution.

Therefore, the percentage of bolts that will have a diameter greater than 0.37 inches is:

P(X>0.37) = 100 - 74.75\\P(X>0.37) = 25.25\%

You might be interested in
Introduced species often thrive and multiply in an environment very different from their original one. Why are they often able t
Anestetic [448]
They begin to adapt into their new location. They then end up having adaptations to help them survive.
8 0
3 years ago
Help
malfutka [58]
The answer for this is 1200N
6 0
2 years ago
Model rocket engines are sized by thrust, thrust duration, and total impulse, among other characteristics. A size C5 model rocke
umka2103 [35]

Answer:

v_{f} = 115.95 m / s

Explanation:

This is an exercise of a variable mass system, let's form a system formed by the masses of the rocket, the mass of the engines and the masses of the injected gases, in this case the system has a constant mass and can be solved using the conservation the amount of movement. Which can be described by the expressions

        Thrust = v_{e}  \frac{dM}{dt}

        v_{f}-v₀ = v_{e} ln ( \frac{M_{o} }{M_{f}} )

where v_{e} is the velocity of the gases relative to the rocket

let's apply these expressions to our case

the initial mass is the mass of the engines plus the mass of the fuel plus the kill of the rocket, let's work the system in SI units

       M₀ = 25.5 +12.7 + 54.5 = 92.7 g = 0.0927 kg

     

The final mass is the mass of the engines + the mass of the rocket

      M_{f} = 25.5 +54.5 = 80 g = 0.080 kg

thrust and duration of ignition are given

       thrust = 5.26 N

       t = 1.90 s

Let's start by calculating the velocity of the gases relative to the rocket, where we assume that the rate of consumption is linear

          thrust = v_{e} \frac{M_{f} - M_{o}  }{t_{f} - t_{o}  }

          v_{e} = thrust  \frac{\Delta t}{\Delta M}

          v_{e} = 5.26 \frac{1.90}{0.080 -0.0927}

          v_{e} = - 786.93 m / s

the negative sign indicates that the direction of the gases is opposite to the direction of the rocket

now we look for the final speed of the rocket, which as part of rest its initial speed is zero

            v_{f}-0 = v_{e} ln ( \frac{M_{o} }{M_{f} } )

we calculate

            v_{f} = 786.93 ln (0.0927 / 0.080)

            v_{f} = 115.95 m / s

5 0
3 years ago
Which of these is MOST LIKELY to cause natural pollution?
egoroff_w [7]
What are the options so that I can help.
8 0
3 years ago
Read 2 more answers
An airplane traveling 919 m above the ocean at 505 m/s is to drop a case of twinkies to the victims below. How much time before
Elena L [17]

Answer:

a. 13.7 s b. 6913.5 m

Explanation:

a. How much time before being directly overhead should the box be dropped?

Since the box falls under gravity we use the equation

y = ut - 1/2gt² where y = height of plane above ocean = 919 m, u = initial vertical velocity of airplane = 0 m/s, g = acceleration due to gravity = -9.8 m/s² and t = time it takes the airplane to be directly overhead.

So,

y = ut - 1/2gt²

y = 0 × t - 1/2gt²

y = 0 - 1/2gt²

y = - 1/2gt²

t² = -2y/g

t = √(-2y/g)

So, t = √(-2 × 919 m/-9.8 m/s²)

t = √(-1838 m/-9.8 m/s²)

t = √(187.551 m²/s²)

t = 13.69 s

t ≅ 13.7 s

So, the box should be dropped 13.69 s before being directly overhead.

b. What is the horizontal distance between the plane and the victims when the box is dropped?

The horizontal distance x between plane and victims, x = speed of plane × time it takes for box to drop = 505 m/s × 13.69 s = 6913.45 m ≅ 6913.5 m

6 0
3 years ago
Other questions:
  • A fixed mass of an ideal gas is heated from 50 to 80℃ at a constant pressure of (a) 1 atm and (b) 3 atm. for which case do you t
    6·1 answer
  • A stone is thrown vertically upward with a speed of 24.0 ms. (a) How fast is it moving when it reaches a height of 13.0 m? (b) H
    13·1 answer
  • Delete question please
    15·1 answer
  • what are two benefits of scientists using a diagram to model the water cycle A It can Show changes that Occur in many Diffrent p
    6·1 answer
  • Max is gearing up for her lacrosse match. What safety measures can help Max stay safe for the big event?
    10·1 answer
  • What could people do to DECREASE erosion of the Earth’s surface? A) Cut down more trees. B) Use more land to plant crops. C) All
    12·2 answers
  • Which of the following would increase friction?
    14·1 answer
  • What is true about the inertia of two cars , car A of mass 1,500 kilograms and car B of mass 2,000 kilograms?
    15·1 answer
  • A man claims that he can hold onto a 16.0-kg child in a head-on collision as long as he has his seat belt on. Consider this man
    10·1 answer
  • On what evidence do you accept the statement,"Aboslute zero is at -273."​
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!