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TiliK225 [7]
3 years ago
13

When you go for a walk which of the following forces is paired with the force of friction on your shoe

Physics
1 answer:
Ann [662]3 years ago
7 0

Answer:

static

Explanation:

static friction pushes in the direction you are walking.

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Mr. Llama walked from his house to the bus stop. The bus stop is 2 miles from his house. He returned back to his house from the
Hoochie [10]

Answer:

Displacement of Mr. Llama: Option D. 0 miles.

Explanation:

The magnitude of the displacement of an object is equal to the distance between its final position and its initial position. In other words, as long as the initial and final positions of the object stay unchanged, the path that this object took will not affect its displacement.

For Mr. Llama:

  • Final position: Mr. Llama's house;
  • Initial position: Mr. Llama's house.

The distance between the final and initial position of Mr. Llama is equal to zero. As a result, the magnitude of Mr. Llama's displacement in the entire process will also be equal to zero.

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3 years ago
According to the Big Bang theory timeline, all matter and energy was compressed into a very small volume at an extremely high te
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The answer i know  is True


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3 years ago
What is the main cause of twice-daily tides around the world?<br><br><br> Help me.
liraira [26]

<em>The main cause of twice-daily tides around the world are;</em>

Gravitational pull of the moon

<u>Tides are the rise and fall of water caused by gravitational forces of the moon and sun on the oceans of the earth. </u>

<u>The moons gravity is large enough to actually pull water out of the ocean from space. Just enough to create motion of the tides.</u>

4 0
3 years ago
A resistor with an unknown resistance is connected in parallel to a 13 Ω resistor. When both resistors are connected in parallel
larisa86 [58]

Answer:

R2 = 10.31Ω

Explanation:

For two resistors in parallel you have that the equivalent resistance is:

\frac{1}{R_{eq}}=\frac{1}{R_1}+\frac{1}{R_2}\\\\      (1)

R1 =  13 Ω

R2 = ?

The equivalent resistance of the circuit can also be calculated by using the Ohm's law:

I=\frac{V}{R_{eq}}\\\\R_{eq}=\frac{V}{I}            (2)

V: emf source voltage = 23 V

I: current = 4 A

You calculate the Req by using the equation (2):

R_{eq}=\frac{23V}{4A}=5.75\Omega

Now, you can calculate the unknown resistor R2 by using the equation (1):

\frac{1}{R_2}=\frac{1}{R_{eq}}-\frac{1}{R_1}\\\\R_2=\frac{R_{eq}R_1}{R_1-R_{eq}}\\\\R_2=\frac{(5.75\Omega)(13\Omega)}{13\Omega-5.75\Omega}=10.31\Omega

hence, the resistance of the unknown resistor is 10.31Ω

8 0
3 years ago
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The acceleration due to gravity on the moon is about 5.4ft/s2. if your weight is 150lbf on earth
Ivenika [448]

... then your weight is <em>25.2 lbf</em> on the moon.

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