3 years ago

What are the values of x for which the denominator is equal to zero for y= -x+4/xx+6X+8

Mathematics

1 answer:

Veseljchak [2.6K]3 years ago

8 0

Answer:

-4 and -2

Step-by-step explanation:

(X+4)(x+2)

4×2=8

4+2=6

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AnnZ [28]

Answer:

B) $g(x) - h(x) = 3x^3 - 5x^2 - 15x + 15$

Step-by-step explanation:

Here, the given functions are:

$g(x) = 5x^2- 10x + 9 \\h(x) = -3x^3+ 5x - 6$

Now, g(x) - h(x) is :

$(5x^2- 10x + 9) - ( -3x^3+ 5x - 6)\\= 5x^2- 10x + 9 + 3x^3 - 5x + 6\\= 3x ^3 + 5x ^2+ (-10 x - 5 x) + (9 + 6)\\= 3x^3 - 5x^2 - 15x + 15$

⇒ $(5x^2- 10x + 9) - ( -3x^3+ 5x - 6) = 3x^3 - 5x^2 - 15x + 15$

B) Hence, $g(x) - h(x) = 3x^3 - 5x^2 - 15x + 15$

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Answer:

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Step-by-step explanation:

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