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3 years ago

How many hundredths are in 2.00?

2 answers:

3 0

So 1 hundreth is 1/100 or 0.01

so how many 0.01 are in 2.00
we know that 100 of 0.01 is 1 and 2 is twice of 1 so there are 200 hundreths in 2.00

atroni [7]3 years ago

3 0

Zero is in the hundredths place. The hundredths place is 2 spaces to the right behind the decimal place. ex: after the decimal place going towards your right, the first place value is your tenth place....the next value place moving towards the right is the hundreths....the next one moving towards the right is your thousanths...and so on...

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Expand and simplify (n-2)(3n+7) + 2n(2n+3)

KonstantinChe [14]

3n^2+7n-6n-14+4n^2+6n= 7n^2+7n-14

Hope that helps and best of wishes!

6 0

3 years ago

What is the word form of 602107

Tcecarenko [31]

Six hundred two thousand hundred seven.

7 0

3 years ago

Read 2 more answers

What is 4(x-2)=4x+10

Effectus [21]

Answer: No Real Answers

Step-by-step explanation:

1. Distribute

4x-8=4x+10

2. Get variables to one side add 8, subtract 4x)

0 = 18

3. Since this statement is false, the answer is... No real answers

3 0

3 years ago

Read 2 more answers

GIVING BRAINLIEST!! HELP PLEASE!! you don't have to make it perfect. (no links/spam/or stealing points. i will report your accou

choli [55]

<h2>Answer:</h2>

C = 2πr

r = C/2π ...(1)

A = πr²

A = π(C/2π)² = πC²/4π²

A = C²/4π.

Correct choice - [A] A = C²/4π.

6 0

2 years ago

Use the Fundamental Theorem of Calculus to find the area of the region between the graph of the function x5 + 8x4 + 2x2 + 5x + 1

belka [17]

Answer:

The area of the region between the graph of the given function and the x-axis = 25,351 units²

Step-by-step explanation:

Given x⁵ + 8 x⁴ + 2 x² + 5 x + 15

If 'f' is a continuous on [a ,b] then the function

$F(x) = \int\limits^a_b {f(x)} \, dx$

By using integration formula

$\int{x^n} \, dx = \frac{x^{n+1} }{n+1} +c$

Given x⁵ + 8 x⁴ + 2 x² + 5 x + 15 in the interval [-6,6]

$\int\limits^6_^-6} (x^{5} + 8 x^{4} + 2 x^{2} + 5 x + 15) )dx$

On integration , we get

= $(\frac{x^{6} }{6} + \frac{8 x^{5} }{5} + 2 \frac{x^{3} }{3} +\frac{5 x^{2} }{2} + 15 x)^{6} _{-6}$

$F(x) = \int\limits^a_b {f(x)} \, dx = F(b) -F(a)$

= $(\frac{6^{6} }{6} + \frac{8 6^{5} }{5} + 2 \frac{6^{3} }{3} +\frac{5 6^{2} }{2} + 15X 6) - ((\frac{(-6)^{6} }{6} + \frac{8 (-6)^{5} }{5} + 2 \frac{(-6)^{3} }{3} +\frac{5 (-6)^{2} }{2} + 15 (-6))$