Prove that the two circles below are similar
B is doubled in sizer then d
Answer:
The equation of the required line is y = x + 5
Step-by-step explanation:
The equation of the given line is y = x - 2
The required line = A line parallel to the given line
The point through which the required line passes = (-3, 2)
The general form of the equation of a straight line, is y = m·x + c
Where;
m = The slope of the line
By comparison, the slope of the given line, m = 1
When two lines are parallel, their slope are equal
Therefore, the slope of the required line = m = 1
The equation of the required line in point and slope form is therefore;
y - 2 = x - (-3) = x + 3
∴y = x + 3 + 2 = x + 5
The equation of the required line is therefore;
y = x + 5.
Answer:
c. y = -35*x + 105
Step-by-step explanation:
Lo que demos hacer es calcular los puntos cuando x = 0 y cuando x = 3, es decir el inicio y el fin del recorrido.
Cuando x es igual 0, y = 105, por lo tanto, la función sería:
y = A*x + 105
Cuando x = 3, y = 0, por lo tanto:
0 = 3*A + 105
resolvemos para A:
3*A = -105
A = -105/3
A = -35
Por lo tanto la función es:
y = -35*x + 105
es decir, la opción c.
Answer:
B. 200 doses
Step-by-step explanation:
Given,
1 dose is required for 100 mg,
Since, 1 mg = 0.001 g,
⇒ 100 mg = 0.1 g
⇒ 1 dost is required for 0.1 g,
Thus, the ratio of doses and quantity ( in gram ) is ![\frac{1}{0.1}=10](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B0.1%7D%3D10)
Let x be the doses required for 20 grams,
So, the ratio of doses and quantity is ![\frac{x}{20}](https://tex.z-dn.net/?f=%5Cfrac%7Bx%7D%7B20%7D)
![\implies \frac{x}{20}=10](https://tex.z-dn.net/?f=%5Cimplies%20%5Cfrac%7Bx%7D%7B20%7D%3D10)
![\implies x=200](https://tex.z-dn.net/?f=%5Cimplies%20x%3D200)
Hence, 200 doses can be obtained from 20 grams of the drug.
Option 'B' is correct.
<span>2/5 would be one...tell me if you need more.</span>