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Vlad1618 [11]
2 years ago
10

Functions please help

Mathematics
1 answer:
Irina18 [472]2 years ago
5 0

Answer:

Step-by-step explanation:

A) 700 cookies in 7 days.

im not sure of B

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Write each fraction in its<br> simplest form.<br> 8<br> 8<br> II<br> 25
WINSTONCH [101]

Answer:

\frac{88}{5^{2} }

Step-by-step explanation:

There are no fractions I am assuming the fraction is 88/25 which would be 88/5^2

5 0
3 years ago
The temperature of a pot of water was 180.3°F and it cooled at a rate of -2.5°F for a minute after 20 minutes what was the tempe
kykrilka [37]
Temperature after 20 minutes is found by multiplying-2.5 by 20 since it goes down by 2.5 degrees for one minute. -2.5 * 20 = -50. Adding this to 180.3 will give the temperature 130.3 degrees.
7 0
3 years ago
Please help me<br> thanks
attashe74 [19]

..no lo sé, pero como necesito puntos, ¿sí?

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2 years ago
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anygoal [31]
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7 0
1 year ago
Read 2 more answers
If f(x)=2x^2+(1000/x), find the average rate of change of f(x) from x=a to x=a+h.
galina1969 [7]

Answer:

\frac{\frac{1000}{x+h}-\frac{1000}{x}}{h} is your average rate of change,

Step-by-step explanation:

average rate of change is

\frac{f(a+h)-f(a)}{a+h-a}, by slope formula

simplify this to get \frac{f(a+h)-f(a)}{h}, which is the definition of the derivative as h goes to 0

\lim_{h \to 0} \frac{f(a+h)-f(a)}{h}

since you defined x=a, we can substitute a for x and vice versa to find our derivative.

\lim_{h \to 0} \frac{(2x^2+\frac{1000}{x+h})-(2x^2+\frac{1000}{x})}{h}

simplifying

\lim_{h \to 0} \frac{\frac{1000}{x+h}-\frac{1000}{x}}{h} (your average rate of change)

6 0
3 years ago
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