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anastassius [24]
3 years ago
15

Question is in the image, thank you

Mathematics
1 answer:
Alex787 [66]3 years ago
6 0

sin H = Opposite / Hypotenuse

sin H = 5/13

sin H = 0.384615

<H = 22.6198

<H = 23 (nearest degree)

Answer is first one.

23

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Please help!
AfilCa [17]

Answer:

a.) P(HH|C)=2/5

Explanation:

Given following:

  • P(HH) = 7
  • P(C) = 10
  • P(HH ∩ C) = 4
  • P(HH ∪ C) = 13

Solving steps:

\sf P(HH|C) = \dfrac{P(HH \cap C) }{P(C)}

\sf P(HH|C) = \dfrac{4 }{10}

\sf P(HH|C) = \dfrac{2 }{5}

8 0
2 years ago
Two race cars,car x an y,are at the starting point of a two km track at the same time.car x and car y make one lap every 60 s an
tino4ka555 [31]

Answer is attached.

Please check the image.

4 0
3 years ago
Whats 14.635 rounded to the nearest cent?
Nutka1998 [239]
The cents are .635 and the greatest cent is 6. So, when it is rounded to the greatest value like estimating it will be 14.600 or 14.6. As easy as that. :)
7 0
3 years ago
georgina works on the 30th floor of a office building she took the elevator to the cafeteria on the 7th floor how many floors di
dezoksy [38]
She traveled 23 floors, 30-7=23.
3 0
3 years ago
Read 2 more answers
A company with a large fleet of cars wants to study the gasoline usage. They check the gasoline usage for 50 company trips chose
Nookie1986 [14]

Answer:

The 95% confidence interval is given by (25.71536 ;28.32464)

And if we need to round we can use the following excel code:

round(lower,2)

[1] 25.72

round(upper,2)

[1] 28.32

And the interval would be (25.72; 28.32)  

Step-by-step explanation:

Notation and definitions  

n=50 represent the sample size  

\bar X= 27.2 represent the sample mean  

s=5.83 represent the sample standard deviation  

m represent the margin of error  

Confidence =88% or 0.88

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

Calculate the critical value tc  

In order to find the critical value is important to mention that we don't know about the population standard deviation, so on this case we need to use the t distribution. Since our interval is at 88% of confidence, our significance level would be given by \alpha=1-0.88=0.12 and \alpha/2 =0.06. The degrees of freedom are given by:  

df=n-1=50-1=49  

We can find the critical values in R using the following formulas:  

qt(0.06,49)

[1] -1.582366

qt(1-0.06,49)

[1] 1.582366

The critical value tc=\pm 1.582366  

Calculate the margin of error (m)  

The margin of error for the sample mean is given by this formula:  

m=t_c \frac{s}{\sqrt{n}}  

m=1.582366 \frac{5.83}{\sqrt{50}}=14.613  

With R we can do this:

m=1.582366*(5.83/sqrt(50))

m

[1] 1.304639

Calculate the confidence interval  

The interval for the mean is given by this formula:  

\bar X \pm t_{c} \frac{s}{\sqrt{n}}  

And calculating the limits we got:  

27.02 - 1.582366 \frac{5.83}{\sqrt{50}}=25.715  

27.02 + 1.582366 \frac{5.83}{\sqrt{50}}=28.325

Using R the code is:

lower=27.02-m;lower

[1] 25.71536

upper=27.02+m;upper

[1] 28.32464

The 95% confidence interval is given by (25.71536 ;28.32464)  

And if we need to round we can use the following excel code:

round(lower,2)

[1] 25.72

round(upper,2)

[1] 28.32

And the interval would be (25.72; 28.32)  

6 0
3 years ago
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