Answer: The nearest tenth would be 150.
Step-by-step explanation:
To round a number to the nearest tenth , look at the next place value to the right (the hundredths).
Answer:
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Let us say that:
K = age of Kristen
B = age of Ben
From the problem, we make the equations:
eqtn 1: K + B = 32
eqtn 2: (K – 4) = 2 (B – 4)
Simplifying eqtn 2:
K – 4 = 2 B – 8
K = 2 B – 4
Plugging in this to eqtn 2:
(2 B – 4) + B = 32
3 B – 4 = 32
3 B = 36
B = 12
From eqtn 2:
K = 2 B – 4 = 2 (12) – 4 = 20
So Kristen is 20 while Ben is 12.
The possible digits are:
5, 6, 7, 8 and
9. Let's mark the case when the locker code begins with a prime number as
A and the case when <span>the locker code is an odd number as
B. We have
5 different digits in total,
2 of which are prime (
5 and
7).
First propability:
</span>

<span>
By knowing that digits don't repeat we can say that code is an odd number in case it ends with
5, 7 or
9 (three of five digits).
Second probability:
</span>
Answer:

Step-by-step explanation:
<u><em>The complete options are</em></u>
a) x - 2y = 30
b) 4x - 3y = 30
c) 3x - 4y = 30
d) 6x - 6y = 30
The given equation is

<u>Verify option d</u>
we have

Divide by 6 both sides



therefore
and
are equivalent