А masdOf 500kg a raised to a height of 6m In 30sFind (a) Workdone .
1 answer:
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Answer:
the energy increases 4 times
Explanation:
A spring has an elastic potential energy that is given by the expression
K_e = ½ K (x-x₀)²
where x is the distance from the equilibrium point and k is the return constant
if the spring is stretched at x-x₀ = 2x₀, the energy value
K_e = ½ k (2x₀)²
K_e = ½ k 4 x₀²
K_e = 4 (½ k x₀²)
= 4
therefore the energy increases 4 times
Answer:
25 m/s
Explanation:
First of all, we can find the acceleration the object by using Newton's second law of motion:
where
F = 20.0 N is the net force applied on the object
m = 4.0 kg is the mass of the object
a is its acceleration
Solving for a, we find
Now we know that the motion of the object is a uniformly accelerated motion, so we can find its final velocity by using the following suvat equation:
where
v is the final velocity
u = 0 is the initial velocity
is the acceleration
t = 5 s is the time
By substituting,