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Wewaii [24]
3 years ago
13

А masdOf 500kg a raised to a height of 6m In 30sFind (a) Workdone .​

Physics
1 answer:
Mazyrski [523]3 years ago
5 0

Answer:

Work done is 882000joule.

power is 29400watt.

Explanation:

given,

Mass(m)=500kg

Acceleration due to gravity(g)=9.8m/s²

Height(h)=6m

Time taken(t)=30s

Workdone=?

Power=?

now,

workdone=force*displaxement

= m*g*h

=500*9.8*6

=8,82,000joule

so, the work done by the man is 8,82,000joule.

then,

power=workdone/time taken

=8,82,000/30

=29,400watt

so, the required power to lift a load is 29,400watt.

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Three perfectly polarizing sheets are spaced 2?cm {\rm cm} apart and in parallel planes. The transmission axis of the second she
Agata [3.3K]

Answer:

I₃/Io % = 0.8.59

Explanation:

A polarizer is a complaint sheet for light in the polarization direction and blocks the perpendicular one. When we use two polarizers the transmission between them is described by Malus's law

      I = I₀ cos² θ

Let's apply the previous exposures in our case, the light is indicatively not polarized, so the first polarized lets half of the light pass

      I₁ = ½ I₀

The light transmitted by the second polarizer

     I₂ = I₁ cos²  θ

     I₂ = (½ I₀) cos2 28

The transmission by the polarizing  third is

     I₃ = I₂ cos²  θ₃    

The angle of the third polarizer with respect to the second is

     θ₃ = 90-28

      θ₃ = 62º

I₃ = (½ I₀ cos² 28 cos² 62)

Let's calculate

I₃ = Io ½ 0.7796 0.2204

I₃ = Io 0.0859

I₃/Io= 0.0859    100

I₃/Io % = 0.8.59

4 0
4 years ago
SOMEONE HELP  ASAP PLSS
kirill115 [55]

–0.05 m/s

Explanation:

The total momentum of the system player+basketball must be conserved before and after the ball has been thrown.

Before throwing the ball, the total momentum of the system is zero, because can assume both the player and the basketball being at rest:

p_i

The total momentum after the ball has been thrown is instead the sum of the momenta of the the player and of the basketball:

p_f=m_p v_p + m_b v_b

where

m_p = 59 kg is the player's mass

v_p is the player's velocity

m_b=0.51 kg is the ball's mass

v_b=6 m/s is the ball's velocity

For the conservation of momentum, we have

p_i=p_f

0=m_p v_p + m_b v_b

v_p=-\frac{m_b v_b}{m_p}=-\frac{(0.51 kg)(6 m/s)}{59 kg}=-0.05 m/s

And the negative sign means that the player travels in the opposite direction to the ball.

8 0
3 years ago
Read 2 more answers
What is the average speed of a car that travels 60 meters in 2<br> seconds?
blondinia [14]

Answer:

30 m/s

Explanation:

Speed is distance over time. 60 meters / 2 seconds, = 30 m/s.

6 0
3 years ago
In Space, an astronaut releases a wrench from his hand. The wrench has a mass of 4 grams and is traveling with a velocity of -15
Vladimir [108]

Answer:

v_2=8.85\times 10^{-4}\ m/s

Explanation:

We have,

Mass of a wrench, m₁ = 4 g = 0.004 kg

Speed of wrench, v₁ = -15 m/s

Mass of the Astronaut, m₂ = 70 kg

It is required to find Astronaut's velocity. Let it is v₂. Using the conservation of linear momentum to find it.

m_1v_1=m_2v_2\\\\v_2=\dfrac{m_1v_1}{m_2}\\\\=\dfrac{0.004\times (-15)}{70}\\\\=-8.85\times 10^{-4}\ m/s

So, his velocity is 8.85\times 10^{-4}\ m/s.

8 0
3 years ago
1. While John is traveling along an interstate highway, he notices a 160-mile marker as he passes through town. Later John passe
pogonyaev

Number of miles that marker shows when passes through town= 160 miles.

Number of miles that marker shows currently to John = 115 miles.

We need to find the distance between town and John's current location.

For the problem, we can clearly see that Town is at 160 miles away but when John passes the marker shows 115 miles.

So, it's just the difference between 160 miles and 115 miles.

In order to find that difference, we need to subtract those two numbers.

160miles - 115miles = 45 miles.

So, we could say the distance between town and John's current location is 45 miles.

4 0
3 years ago
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