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Wewaii [24]
3 years ago
13

А masdOf 500kg a raised to a height of 6m In 30sFind (a) Workdone .​

Physics
1 answer:
Mazyrski [523]3 years ago
5 0

Answer:

Work done is 882000joule.

power is 29400watt.

Explanation:

given,

Mass(m)=500kg

Acceleration due to gravity(g)=9.8m/s²

Height(h)=6m

Time taken(t)=30s

Workdone=?

Power=?

now,

workdone=force*displaxement

= m*g*h

=500*9.8*6

=8,82,000joule

so, the work done by the man is 8,82,000joule.

then,

power=workdone/time taken

=8,82,000/30

=29,400watt

so, the required power to lift a load is 29,400watt.

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Betty (mass 40 kg), standing on slippery ice, catches her leaping dog (mass 15 kg) moving horizontally at 3.0 m/s. Show that the
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Answer:

v = 2.18m/s

Explanation:

In order to calculate the speed of Betty and her dog you take into account the law of momentum conservation. The total momentum before Betty catches her dog must be equal to the total momentum after.

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Mv_{1o}+mv_{2o}=(M+m)v        (1)

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v: speed of both Betty and her dog = ?

You solve the equation (1) for v:

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The speed fo both Betty and her dog is 2.18m/s

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A water bottle contains 15.0 ounces of water. A person drinks 0.5 ounces per minute. How many hours will it take to drink all of
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A runner moves 2.88 m/s north. She accelerates at 0.350 m/s^2 at a -52.0 angle. At the point in the motion where she is running
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The runner has initial velocity vector

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and acceleration vector

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It's not clear what you're supposed to find at this particular time... possibly her position vector? In that case, assuming she starts at the origin, her position at time t would be

\vec x=\vec v_0t+\dfrac12\vec at^2

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