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Snowcat [4.5K]
3 years ago
12

Which of the following did not occur during the collapse of the solar nebula?

Physics
1 answer:
vaieri [72.5K]3 years ago
7 0
If this is one of the following, it's correct
<span>"concentrating denser materials nearer the sun"
I hope this helps!
My source is Quizlet</span>
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A bodybuilder loads a bar with 550 Newtons (~125 pounds) of weight and pushes the bar over her head 10 times. Each time she lift
mafiozo [28]

Work = (force) x (distance)

Each time she lifts the weight, she does

          (550 N) x (0.5 m) = 275 joules of work against gravity.

Each time she lets the bar down gently, gravity does

          (550 N) x (0.5 m) = 275 joules of work against her muscles. 

If the human physical muscular system were 100% efficient, and capable
of absorbing work as well as spending it, then the bodybuilder would do
exactly zero work in the process of 1-up followed by 1-down.


3 0
3 years ago
Read 2 more answers
An engine develops 500 Nm of torque at 3900 rev/min. The power developed by the engine is ...
Oduvanchick [21]

Answer:

204kW

Explanation:

P = t x ω = 500 x (2πx3900/60) = 204203W = 204kW

3 0
3 years ago
Which of the following involves an endothermic reaction?
pav-90 [236]
The answer would be c
8 0
3 years ago
Read 2 more answers
In 1995 a research group led by Eric Cornell and Carl Wiemann at the University of Colorado successfully cooled Rubidium atoms t
saveliy_v [14]

Answer:

0.00493 m/s

Explanation:

T = Temperature of the isotope = 85 nK

R = Gas constant = 8.341 J/mol K

M = Molar mass of isotope = 86.91 g/mol

Root Mean Square speed is given by

v_r=\sqrt{\dfrac{3RT}{M}}\\\Rightarrow v_r=\sqrt{\dfrac{3\times 8.314\times 85\times 10^{-9}}{86.91\times 10^{-3}}}\\\Rightarrow v_r=0.00493\ m/s

The Root Mean Square speed is 0.00493 m/s

6 0
3 years ago
A sphere of radius r = 5cm carries a uniform volume charge density rho = 400 nC/m^3. Q. What is the total charge Q of the sphere
Tanzania [10]

Answer:

The total charge Q of the sphere is 2.094\times10^{-10}\ C.

Explanation:

Given that,

Radius = 5 cm

Charge density J= 400\ nC/m^3

We need to calculate the total charge Q of the sphere

Using formula of charge

q=\rho V

Where, \rho = charge density

V = volume

Put the value into the formula

q=\rho\times(\dfrac{4}{3}\pi r^3)

Put the value into the formula

q=\dfrac{4}{3}\times\pi\times400\times10^{-9}\times(5\times10^{-2})^3

q=2.094\times10^{-10}\ C

Hence, The total charge Q of the sphere is 2.094\times10^{-10}\ C.

6 0
3 years ago
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