3 years ago

Which of the following did not occur during the collapse of the solar nebula?

1 answer:

7 0

If this is one of the following, it's correct
<span>"concentrating denser materials nearer the sun"
I hope this helps!
My source is Quizlet</span>

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What is the speed of sound in air at 40°C?

Blababa [14]

343 meters per second Is the answer

4 0

3 years ago

Read 2 more answers

1. Which of the following is an accurate statement? A. Step-down voltage transformers have a different number of turns in the pr

Snowcat [4.5K]

'C' is the only true statement on the list.

Step-up voltage transformers have a lower number of turns
in the primary than in the secondary winding.

4 0

3 years ago

2)It is known that the connecting rodS exerts on the crankBCa 2.5-kN force directed down andto the left along the centerline ofA

11111nata11111 [884]

Answer:

M_c = 100.8 Nm

Explanation:

Given:

F_a = 2.5 KN

Find:

Determine the moment of this force about C for the two cases shown.

Solution:

- Draw horizontal and vertical vectors at point A.

- Take moments about point C as follows:

M_c = F_a*( 42 / 150 ) *144

M_c = 2.5*( 42 / 150 ) *144

M_c = 100.8 Nm

- We see that the vertical component of force at point A passes through C.

Hence, its moment about C is zero.

5 0

3 years ago

Why does it take much longer time and distance to stop a moving ship in water than a moving car on the road

Naddik [55]

The force on the ship is more than a car

6 0

3 years ago

If the magnitude of the magnetic field is 2.50 mT at a distance of 12.6 cm from a long straight current carrying wire, what is t

Aleksandr-060686 [28]

Answer:

The magnetic field at a distance of 19.8 cm from the wire is 1.591 mT

Explanation:

Given;

first magnetic field at first distance, B₁ = 2.50 mT

first distance, r₁ = 12.6 cm = 0.126 m

Second magnetic field at Second distance, B₂ = ?

Second distance, r₂ = ?

Magnetic field for a straight wire is given as;

$B = \frac{\mu I}{2 \pi r}$

Where:

μ is permeability

B is magnetic field

I is current flowing in the wire

r distance to the wire

$Let \ \frac{\mu I}{2\pi} \ be \ constant; = K\\\\B = \frac{K}{r} \\\\K = Br\\\\B_1r_1 = B_2r_2\\\\B_2 =\frac{B_1r_1}{r_2} \\\\B_2 = \frac{2.5*10^{-3} *0.126}{0.198} \\\\B_2 = 1.591 *10^{-3}\ T\\\\B_2 = 1.591 \ mT$

Therefore, the magnetic field at a distance of 19.8 cm from the wire is 1.591 mT

7 0

3 years ago