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Sophie [7]
3 years ago
11

Identify a pattern in the given list of numbers. Then use this pattern to find the next number.

Mathematics
1 answer:
Rom4ik [11]3 years ago
8 0

Answer:

The given sequence is geometric sequence

In the given pattern we have next number is a_5=\frac{1}{4}

Step-by-step explanation:

Given numbers are 64,-16,4,-1

To identify the pattern of the given numbers :

Let a_1=64, a_2=-16 ,a_3=4  and a_4=-1

To find the next number that is a_5

common ratio r=\frac{a_2}{a_1}

=\frac{-16}{64}

r=-\frac{1}{4}

r=\frac{a_3}{a_2}

=\frac{4}{-16}

r=-\frac{1}{4}

Therefore the common ration is r=-\frac{1}{4}

Therefore the given sequence is geometric sequence

The nth term of the geometric sequence is a_n=a_1r^{n-1}

Now find the 5th term so put n=5 , a_1=64andr=\frac{-1}{4} we have

a_5=64(\frac{-1}{4})^{5-1}

=64(\frac{-1}{4})^{4}

=64(\frac{1}{4})^{4}

=64(\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4})

=\frac{1}{4}

Therefore a_5=\frac{1}{4}

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a biologist counted 15 squirrels in 3 acres of forest. based on that data how many squirrels would be expected yo inhabit a 275
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Step-by-step explanation:

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4 years ago
It takes Max 5.5 minutes to do 60 pull ups which includes a break in between. It takes him 8 minutes to do 120 pull ups which in
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Answer: 648 pull-ups

Step-by-step explanation:

Given

Max take 5.5 minutes to do 60 Pull-ups with a break in between

Similarly, it took 8 minutes for 120 pull-ups

Suppose the time taken for a single pull-up and break is x and y  minutes

So, it can be written

\Rightarrow 60x+y=5.5\quad \ldots(i)\\\Rightarrow 120x+y=8\quad \ldots(ii)\\\\\text{Solve (i) and (ii) we get}\\\\x=\dfrac{2.5}{60}\ min \ or\ \ 2.5\ s\\\\y=3\ min

Now, suppose max perform at this rate, and the total pull-ups are P in 30 minutes

\therefore P\times \dfrac{2.5}{60}+3=30\\\\\Rightarrow P\times \dfrac{2.5}{60}=27\\\\\Rightarrow P=648\ \text{Pull-ups}

4 0
3 years ago
Ball kicked into the air with an initial upward velocity of 60 ft/s. It’s height h in feet after t seconds is given by the funct
Free_Kalibri [48]

Answer:

Max height: 61.25 feet

Max height reached at 15/8 seconds, or 1.875 seconds

How long to hit the ground: (15 + 7√5)/8  or about 3.83 seconds

How high after 1 second:  49 feet

Step-by-step explanation:

Since the function is a quadratic representing height, and the coefficient of the t² is negative, the vertex of the parabola will be the maximum height achieved by the ball.  

The general form for a quadratic equation is ax² + bx + c,

 here a is -16, and b is 60

 

To find the x coordinate of the vertex, use   x = -b/(2a)

  We have x = -60/[2(-16)]

                x = -60/-32

                         x = 15/8

So at 15/8 seconds, the ball reaches is maximum height

Now plug that into the equation to find the y value, which will be the height...

y = -16(15/8)² + 60(15/8) + 5  

      y = -16(225/64) + 900/8 + 5

     y = -225/4 +  450/4 + 20/4

       y =  245/4

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To find out how long the ball was in flight, solve the equation...

0 = -16t² + 60t + 5

    Use quadratic equation...

    x = -60/-32 ± √[60² - 4(-16)(5)]/-32

     x = 15/8 ± (√3920)/-32

      x = 15/8 ± (28√5)/-32

          x = 15/8 ± (-7√5)/8

  so x = (15 - 7√5)/8   and  (15 + 7√5)/8

     (15 - 7√5)/8 is negative, and we're talking about time, so this answer is ignored.  

(15 + 7√5)/8 seconds is when the ball hits the ground

To find out out how high the ball was after 1 second, plug 1 in for x and simplify

h(1) = -16(1²) + 60(1) + 5

 h(1) = -16 + 60 + 5

  h(1) = 49

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