The given question is incomplete. The complete question is as follows.
From the following formula, calculate the quantities required for each of the following ingredients to make 5 lb. (avoir) of hydrophilic ointment. All values to be in g, do not include units in your submitted answer; use no more than 3 decimal places. Convert using 1 lb = 454 g. Note: all values done by mass, including the water, so this is not a q.s situation (volume is irrelevant).
Methylparaben 0.25 g
Propylparaben 0.15 g
Sodium Lauryl Sulfate 10 g
Propylene Glycol 120 g
Stearyl Alcohol 240 g
White Petrolatum 250 g
Purified Water, to make 1000 g
Explanation:
For the given quantities, the sum is 620.4 g. Now, amount of purified water (to make 1000 g of ointment) is as follows.
1000 g - 620.4 g
= 379.6 g
Now, to make 5 lb we will calculate the quantities as follows.
Formula weight = 1000 g
Therefore, desired quantity is as follows.
5 lb = 5 x 454 g
= 2270 g
Hence, this means the factor is calculated as follows.
= 2.27
Now, we will calculate the quantity of each ingredient using factor 2.27 as follows.
-
Methylparaben = 0.25 g x 2.27 = 0.5675 g
-
Propylparaben = 0.15 g x 2.27 = 0.3405 g
-
Sodium Lauryl Sulfate = 10 g x 2.27 = 22.7 g
-
Propylene Glycol = 120 g x 2.27 = 272.4 g
-
Stearyl Alcohol = 240 g x 2.27 = 544.8 g
-
White Petrolatum = 250 g x 2.27 = 567.5 g
-
Purified Water = 379.6 g x 2.27 = 861.692 g
Answer:
a) 5
b) 4
c) 3
d) 3
e) 4
Explanation:
I use only one rule when the decimal is present, meaning you can see the decimal (as is the case with all of these).
When the decimal is Present, start counting sig figs from the Pacific (left) side of the number beginning with the first non-zero digit and count all the way to the end.
So, for example, in "a", the first non-zero digit starting from the left is 1, then continue counting all the way to the right side.
For "c", the first non-zero digit is the left most 4 (skip the first 4 zeros), then count all the way to the right side.
False, there are five forms of matter; solid, liquid, glass, plasma, and <span>Bose-Einstein condensates.
hope this helps :)</span>
Answer:
6626 g
Explanation:
Given that:
Density of water = 1.00 g/ml, volume of water = 42800 ml.
Since density = mass/ volume
mass of water = volume of water * density of water = 42800 ml * 1 g/ml = 42800 g
Initial temperature of water = 22°C and final temperature of water = 45°C.
specific heat capacity for water = 4.184 J/g°C
ΔT water = 45 - 22 = 23°C
For iron:
mass = m,
specific heat capacity for iron = 0.444 J/g°C
Initial temperature of iron = 1445°C and final temperature of water = 45°C.
ΔT iron = 45 - 1445 = -1400°C
Quantity of heat (Q) to raised the temperature of a body is given as:
Q = mCΔT
The quantity of heat required to raise the temperature of water is equal to the temperature loss by the iron.
Q water (gain) + Q iron (loss) = 0
Q water = - Q iron
42800 g × 4.184 J/g°C × 23°C = -m × 0.444 J/g°C × -1400°C
m = 4118729.6/621.6
m = 6626 g
Answer: 11.18atm
Explanation:Please see attachment for explanation
