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Ymorist [56]
3 years ago
12

x g of metal (equivalent wt=12) was completely dissolved in 100 cc of N/2 HCl. The volume was then made upto 500 cc.25 cc of thi

s diluted acid required 17.5 cc N/10 NaOH for complete neutralization. Find the value of x.​
Chemistry
1 answer:
ad-work [718]3 years ago
8 0

Answer:

zxzx

Explanation:

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Is C2S6 ionic or covalent
Stels [109]

Answer:

covalent

Explanation:

C2S6 is a compound made of 2 nonmetals which makes it covalent

Hope this helps! Plz mark brainliest

8 0
4 years ago
There are two opposing processes that occur in a solution in contact with undissolved solute. These are dissolving and ________.
Alex777 [14]

Answer:

c. crystallization

Explanation:

The opposing process that occur in a solution in contact with undissolved solute are dissolution and crystallization.

In the dissolution process the solid substance coverts into liquid state and mixes with solution. Whereas in Crystallization the the chemical is converted from the liquid solution to solid crystal state.

3 0
3 years ago
Calculate the molar solubility of silver chloride in 0.15 M sodium chloride.
Alex777 [14]

Answer:

S = 1.1 × 10⁻⁹ M

Explanation:

NaCl is a strong electrolyte that dissociates according to the following expression.

NaCl(aq) → Na⁺(aq) + Cl⁻(aq)

Given the concentration of NaCl is 0.15 M, the concentration of Cl⁻ will be 0.15 M.

We can find the molar solubility (S) of AgCl using an ICE chart.

      AgCl(s) ⇄ Ag⁺(aq) + Cl⁻(aq)

I                         0            0.15

C                      +S              +S

E                        S            0.15+S

The solubility product (Ksp) is:

Ksp = 1.6 × 10⁻¹⁰ = [Ag⁺].[Cl⁻] = S (0.15 + S)

If we solve the quadratic equation, the positive result is S = 1.1 × 10⁻⁹ M

6 0
3 years ago
Read 2 more answers
CH4 + 202 → CO2 + 2H2O
ohaa [14]
It’s a combustion reaction but what are you trying to find?
6 0
2 years ago
Calculate hydrochloric acid (umol)in 200 ul of a<br> 0.5173Msolution of acid?
strojnjashka [21]

<u>Answer:</u> The moles of hydrochloric acid is 1.0346\times 10^{-4}\mu mol

<u>Explanation:</u>

To calculate the molarity of solution, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}

Or,

\text{Molarity of the solution}=\frac{\text{Micro moles of solute}\times 10^6}{\text{Volume of solution (in }\mu L)}}

We are given:

Molarity of solution = 0.5173 M

Volume of solution = 200\mu L

Putting values in above equation, we get:

0.5173M=\frac{\text{Micro moles of HCl}\times 10^6}{200\mu L}\\\\\text{Micro moles of HCl}=1.0346\times 10^{-4}\mu mol

Hence, the moles of hydrochloric acid is 1.0346\times 10^{-4}\mu mol

7 0
3 years ago
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