Question

If you were to separate all of the electrons and protons in 1.00 g (0.001 kg) of matter, you’d have about 96,000 C of positive charge and the same amount of negative charge. If you placed these charges 8.00 m apart, how strong would the attractive forces between them be?

Answer 1

Answer:

The attractive force between them is $1.296 \times 10^{18}$ N

Explanation:

Given:

Charge $q = 96000$ C

Distance between two charges $r = 8$ m

According to the coulomb's law,

    $F = \frac{kq^{2} }{r^{2} }$

Where $k = 9 \times 10^{9}$ = force constant.

   $F = \frac{9 \times 10^{9} \times (96000)^{2} }{8^{2} }$

   $F = 1.296 \times 10^{18}$ N

Therefore, the attractive force between them is $1.296 \times 10^{18}$ N