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maxonik [38]
2 years ago
9

If the electric potential in a region is given by v(x)=7/x2 the x component of the electric field in that region is

Physics
1 answer:
lions [1.4K]2 years ago
6 0

Hi there!

Recall that:
\Delta V = -\int\limits^a_b {E \cdot } \, dx

Given an electric field, the potential difference can be solved by using integration. Similarly:
E = -\frac{dV}{dx}

We can differentiate the electric potential equation to solve for the electric field.

Use the power rule:
\frac{dy}{dx} x^n = nx^{n - 1}

Differentiate the given equation.

-\frac{dV}{dx}\frac{7}{x^2} =- \frac{dV}{dx}7x^{-2} = -(-14x^{-3}) = \frac{14}{x^3}

Or:
\boxed{E(x) = \frac{14}{x^3}}

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artcher [175]
1st derivative gives velocity;
d r(t)/ dt = 2t i + 6 j + 4/t k

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3 years ago
Use this table of a school bus during morning pickups to calculate its average speed between 0 h and 2.340 h.
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The average speed between 0 h and 2.340 h is 6.97 Km/h

Average speed is defined as the total distance travelled divided by the total time taken to cover the distance.

Average \: speed =  \frac{total \: distance}{total \: time}  \\  \\

With the above formula, we can obtain the average speed between 0 h and 2.340 h as illustrated below:

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Average \: speed =  \frac{total \: distance}{total \: time}  \\  \\Average \: speed =  \frac{16.3}{2.340}  \\  \\ Average \: speed = 6.97 \: Km/h \\  \\

Learn more about average speed: brainly.com/question/24884027

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2 years ago
A coat rack weighs 65.0 lbs when it is filled with winter coats and 40.0 lbs when it is empty. The base of the coat rack has an
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Answer:

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Explanation:

First we find the pressure exerted by the rack without coat. So, for that purpose, we use formula:

P₁ = F/A

where,

P₁ = Pressure exerted by empty rack = ?

F = Force exerted by empty rack = Weight of Empty Rack = 40 lb

A = Base Area = 452.4 in²

Therefore,

P₁ = 40 lb/452.4 in²

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Now, we calculate the pressure exerted by the rack along with the coat.

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P₂ = 65 lb/452.4 in²

P₂ = 0.144 psi

Now, the difference between both pressures is:

ΔP = P₂ - P₁

ΔP = 0.144 psi - 0.088 psi

<u>ΔP = 0.056 psi</u>

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