Distance is 90km,time 1 hr
distance 2 is 82km,time 5 hrs
average speed=total distance travelled/total time taken.
90+82=172/5+1=6
average speed=28.7km over hour
Answer:
8.27°
Explanation:
To angle difference will be determined by the difference in the displacement of the springs, produced by the weight of the center of mass of the rod.
by a simple trigonometric relation you obtain that the angle:
hence, the angle between the rod and the horizontal is 8.27°
I believe it’s C, by the air movement
Answer:
Explanation:
<u>Horizontal Launch
</u>
It happens when an object is launched with an angle of zero respect to the horizontal reference. It's characteristics are:
- The horizontal speed is constant and equal to the initial speed
- The vertical speed is zero at launch time, but increases as the object starts to fall
- The height of the object gradually decreases until it hits the ground
- The horizontal distance where the object lands is called the range
We have the following formulas
Where is the initial horizontal speed, is the vertical speed, t is the time, g is the acceleration of gravity, x is the horizontal distance, and y is the height.
If we know the initial height of the object, we can compute the time it takes to hit the ground by using
Rearranging and solving for t
We then replace this value in
To get
The initial speed depends on the initial height y=32.5 m, the range x=107.6 m and g=9.8 m/s^2. Computing
The launch velocity is
From the given information, we don't know. All we can tell is the net effect of all the changes during those 4 seconds ... the "averages".
The average change in speed is an increase of 72 km/hr (20 m/s) during that time.
The average acceleration is a constant 18 km/hr/sec (5 m/s^2) during the same time.
But both the speed and the acceleration may have gone up or down many times during the 4 seconds.