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2 years ago

In __________ waves, the motion of the particles in a medium is along the direction of the wave (parallel). *

Physics

1 answer:

True [87]2 years ago

7 0

Longitude is the answer

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if pete (mass =90.00kg) weighs himself and finds that he weighs 30.0 pounds, how far away from the earth is he?

Svet_ta [14]

Here we know that mass of the person is 90 kg

His weight is given as 30 lbf

so here we can convert it into Newton as we know that

1 lbf = 4.45 N

Now from above conversion

$30 lbf = 30 \times 4.45 = 133.45 N$

now we can use this to find the gravity at this height

$mg = 133.45$

$90\times g = 133.45$

$g = 1.49 m/s^2$

now we know that with height gravity varies as

$g' = g(\frac{R}{R+H})^2$

$1.49 = 9.8(\frac{6.37\times 10^6}{6.37\times 10^6 + h})^2$

$h = 1.0 \times 10^7 m$

so above is the height from the surface of earth

4 0

2 years ago

Which increases the work output of a machine?

Dafna11 [192]

A reducing friction

3 0

3 years ago

Why the watt is called derived unit ?

Yuri [45]

Answer:

It is because it is a unit of Power(which is a derived quantity)

4 0

2 years ago

A 0.4 m long solenoid has a total of 356 turns of wire and carries a current of 79 A. What is the magnitude of the magnetic fiel

Masja [62]

Answer:

B = 0.088 T

Explanation:

Given that,

The length of a solenoid, l = 0.4 m

No. of turns of wire, N = 356

Current, I = 79 A

We need to find the magnitude of the magnetic field at the center of the solenoid. It is given by the formula.

$B=\mu_onI\\\\B=\mu_o \dfrac{N}{l}\times I\\\\B=4\pi \times 10^{-7}\times \dfrac{356}{0.4}\times 79\\\\B=0.088\ T$

So, the magnitude of the magnetic field at the center of the solenoid is 0.088 T.

5 0

2 years ago

A steel ball of mass 3 kg moving at 2.4 m/s to the left hits a stationary, 4 kg glob of clay. The ball becomes imbedded in the c

Kitty [74]

Answer:

V = 1.02 m/s

Explanation:

Given that,

The mass of a steel ball, m₁ = 3 kg

The mass of glob of clay, m₂ = 4 kg

The speed of a steel ball, u₁ = 2.4 m/s

The speed of glob, u₂ = 0 (at rest)

Let V be the combined speed of the system. Using the conservation of energy to find the combined speed.

$V=\dfrac{m_1u_1+m_2u_2}{(m_1+m_2)}\\\\V=\dfrac{3(2.4)+4(0)}{(3+4)}\\\\V=1.02\ m/s$

So, the combined speed is 1.02 m/s in left direction.

3 0

2 years ago