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aliya0001 [1]
3 years ago
5

Graph question pls help thank you!

Physics
2 answers:
Natalka [10]3 years ago
8 0
She is traveling at a constant speed.
azamat3 years ago
5 0

Answer:

she is traveling at a constant

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A 1.5-mole sample of an ideal gas is gently cooled at constant temperature 320 K. It contracts
Alona [7]

Answer:

V₂ = 14.07 L

Explanation:

As this gas is cooled at constant temperature of 320 K, this means that we are on an isothermal process, and according to the 1st law of thermodynamics:

Q = W   (1)

And as the temperature is constant, we can use the following expression to calculate the Work done:

W = nRT ln(V₁/V₂)   (2)

However, as Q = W, we can replace heat into the above expression and then solve for V₂:

Q = nRT ln(V₁/V₂)

Replacing we have:

1200 = (1.5 * 8.314 * 320) ln(19/V₂)

1200 = 39907.2 ln(19/V₂)

ln(19/V₂) = 1200/3990.72

ln(19/V₂) = 0.3007

19/V₂ = e^(0.3007)

V₂ = 19 / e^(0.3007)

<h2>V₂ = 14.07 L</h2>

Hope this helps

6 0
3 years ago
Why does a tail appear when a comet nears the sun?
ahrayia [7]
It heats up. the ice transforms directly from a solid to a vapor, releasing dust particles. the solar wind sweeps the material and it forms what to appears to be a tail.
3 0
3 years ago
120 J of work was done to lift an object 6 m above
Slav-nsk [51]

Answer:

The last option, 20 N and 2.04 kg

Explanation:

work = (force)(distance)

work = 120 joules

distance: 6 m

rearrange to find force:

120=(6)F

F= 120/6 = 20 Newtons.

Assuming its lifted from Earth's surface, the force of gravity will be 9.81 m/s^2. Let's find mass:

F=mg

m=F/g

m=(20)/(9.81)= 2.038 kg

6 0
2 years ago
1. Calculate the total heat content of 10 kg of ice at -23°C.?
vesna_86 [32]

To solve the problem, we must know the heat capacity of ice and water.

For Cp = 2090 J/kg C

H = mCpT

H = (10 kg) ( 2090 J/ Kg C) ( -23 C)

H = - 480700 J

For water Cp = 4180 j/kg C

H = (100 kg) ( 4180 J/kg C) ( 60 C)

<span>H = 2508000 J</span>

8 0
3 years ago
Steam is leaving a 4-L pressure cooker whose operating pressure is 150 kPa. It is observed that the amount of liquid in the cook
Anna71 [15]

Answer:

The mass flow rate is 2.37*10^-4kg/s

The exit velocity is 34.3m/s

The total flow of energy is 0.583 KJ/KgThe rate at which energy leave the cooker is 0.638KW

<u></u>

7 0
2 years ago
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