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aliya0001 [1]
3 years ago
5

Graph question pls help thank you!

Physics
2 answers:
Natalka [10]3 years ago
8 0
She is traveling at a constant speed.
azamat3 years ago
5 0

Answer:

she is traveling at a constant

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Which states the purpose of an experiment?
Whitepunk [10]
B; to produce a hypothesis.

6 0
3 years ago
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A physicist comes across an open container which is filled with two liquids. Since the two liquids have different density, there
Dominik [7]

Answer:

496.57492 kg/m³

Explanation:

P_a = Atmospheric pressure = 101300 Pa

\rho_w = Density of water = 1000 kg/m^3

h_w = Height of water = 21.8 cm

h_f = Height of fluid = 30 cm

g = Acceleration due to gravity = 9.81 m/s²

\rho_f = Density of the unknown fluid

Absolute pressure at the bottom

P_{abs}=P_a+\rho_wgh_w+\rho_fgh_f\\\Rightarrow \rho_f=\frac{P_{abs}-P_a-\rho_wgh_w}{gh_f}\\\Rightarrow \rho_f=\frac{104900-101300-1000\times 9.81\times 0.218}{9.81\times 0.3}\\\Rightarrow \rho_f=496.57492\ kg/m^3

The density of the unknown fluid is 496.57492 kg/m³

6 0
3 years ago
The terminals of a diode are called the
aniked [119]

A diode has two terminals. The positive side is called the anode, and the negative one is called the cathode.

8 0
3 years ago
Read 2 more answers
A person throws a balloon straight down above level ground. The balloon bounces back up into the air. Drag force is significant
love history [14]

Explanation:

   a) Balloon is being thrown down and is speeding up;

           mg > F_drag

  b) Balloon is in the air on its way down and moving with constant speed.

           F_drag =mg

  c) The Balloon is on the ground and rest instantaneously

           mg = Normal

  d) Balloon is moving slowly downward;

   e) Because, at the peak of trajectory drag force  is 0.

             Drag force = 0

5 0
4 years ago
A cliff jumper jumps off a cliff with an initial horizontal velocity of 10 m/s. The cliff is 10 meters high. How far from the ba
nalin [4]

Answer:

The distance reached is 14.3 m.

Explanation:

To find the distance reached by the diamond first we need to find the flight time:

t_{v} = \sqrt{\frac{2h}{g}}

Where:

h: is the height = 10m

g: si the gravity = 9.81 m/s²

t_{v} = \sqrt{\frac{2h}{g}} = \sqrt{\frac{2*10 m}{9.81 m/s^{2}}} = 1.43 s

Now, we can find the distance reached:

x = V_{0_{x}}*t_{v}

Where:

V_{0_{x}} is the initial horizontal velocity = 10 m/s

x = V_{0_{x}}*t_{v} = 10 m/s*1.43 s = 14.3 m

Therefore, the distance reached is 14.3 m.

I hope it helps you!    

3 0
3 years ago
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