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Elenna [48]
3 years ago
10

10 points) A rubber ball and a lump of putty of the same mass m = 0.05 kg are thrown with the same speed v=10.0 m/s in positive

x-direction against a vertical wall. The ball bounces back with the same speed v’=10.0 m/s in negative x-direction. The putty sticks to the wall. Which of the two objects (rubber ball and a lump of putty) experiences the greater momentum change?
Physics
1 answer:
snow_lady [41]3 years ago
4 0

Answer:

the ball experiences the greater momentum change

Explanation:

You have to take into account that momentum change is given by

\Delta p=mv_f-mv_b

where vf and vb are the speed of the object after and before the impact.

In the case of the ball you have

\Delta p=(0.05kg)(-10.0\frac{m}{s})-(0.05kg)(10.0\frac{m}{s})=-1kg\frac{m}{s}

where the minus of vf is included due to the motion is in an opposite direction regarding with vb

And for the lump

\Delta p=(0.05kg)(10.0\frac{m}{s})-(0.05kg)(0\frac{m}{s})=0.5kg\frac{m}{s}

Hence, the ball experiences the greater change

hope this helps!!

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