Answer:
The total amount paid by Gabriel at the local gas station is $70.49.
Step-by-step explanation:
Cost of gasoline per gallon = $2.75
Cost of diesel per gallon = $3.02
Amount of gasoline Gabriel needs = 15.2 gallons
Amount of diesel Gabriel needs = 9.5 gallons
Compute the total amount paid by Gabriel at the local gas station as follows:
Total Cost = Cost of gasoline × Amount of gasoline
+ Cost of diesel × Amount of diesel

Thus, the total amount paid by Gabriel at the local gas station is $70.49.
9514 1404 393
Answer:
55,637.8 square inches
Step-by-step explanation:
We can find side n using the Law of Sines:
n/sin(N) = p/sin(P)
n = p(sin(N)/sin(P)) = 600·sin(64°)/sin(96°)
n ≈ 542.246913 . . . . inches
The angle O is ...
O = 180° -N -P = 180° -64° -96° = 20°
Then the area is ...
A = 1/2·np·sin(O)
A = (1/2)(542.246913 in)(600 in)·sin(20°) ≈ 55,637.81008 in²
The area of ∆NOP is about 55,637.8 in².
Answer:
Fast ball challenge
Step-by-step explanation:
Given
Slow Ball Challenge




Fast Ball Challenge




Required
Which should he choose?
To do this, we simply calculate the expected earnings of both.
Considering the slow ball challenge
First, we calculate the binomial probability that he hits all 7 pitches

Where
--- pitches
--- all hits
--- probability of hit
So, we have:




Using a calculator:
--- This is the probability that he wins
i.e.

The probability that he lose is:
---- Complement rule


The expected value is then calculated as:


Using a calculator, we have:
Considering the fast ball challenge
First, we calculate the binomial probability that he hits all 3 pitches

Where
--- pitches
--- all hits
--- probability of hit
So, we have:



Using a calculator:
--- This is the probability that he wins
i.e.

The probability that he lose is:
---- Complement rule


The expected value is then calculated as:


Using a calculator, we have:

So, we have:
-- Slow ball
--- Fast ball
<em>The expected earnings of the fast ball challenge is greater than that of the slow ball. Hence, he should choose the fast ball challenge.</em>