Answer:
Vamos a inventa tres multiplicaciones de seis factores en la que el resultado sea positivo, es decir un número mayor que cero, en la otra negativo, es decir, un número menor que cero y por último otra multiplicación que de como resultado el cero "0".
Primero recordemos que:
Los factores son los números que se multiplican.
Seis factores serían 6 números.
Multiplicación con resultado positivo, es decir mayor a 0:
2×3×4×2×1×5=240
Multiplicación con resultado negativo, es decir menor a 0:
-4×2×5×2×1×10= -400
Multiplicación con resultado cero:
2×4×6×7×11×0=0
Step-by-step explanation:
Brainliest please
(goh)(x) = (g(x))(h(x)) = (x^2)(x-7) = x^3 -7x^2
then (goh)(5) = (5^3)-7(5)^2 = 124-7(25) = 124-175 = -51
Answer:
b. I and II are both false.
Step-by-step explanation:
I. For a significance level, the two tailed hypothesis is not always accurate than the one tailed hypothesis test. The hypothesis testing is carried to find out the correctness of a claim of a population parameter. The two tail hypothesis test which used both positive and negative tails of the distribution is not always more accurate than one tailed test.
II. The process of the point estimation involves the utilization of the values of a statistic which is obtained from the sample data to obtain the best estimate of a corresponding unknown parameter in the given population.
Hence, both the statements are false.
Answer:
4x^2 -16
Step-by-step explanation:
(2x + 4)(2x - 4)
FOIL
first:2x*2x = 4x^2
outer: -4 *2x = -8x
inner: 4*2x = 8x
last: -4*4 = -16
Add them together
4x^2 -8x+8x =-16
4x^2 -16
Answer:
the probability is 0.311 (31.1%)
Step-by-step explanation:
defining the event L= being late to work :Then knowing that each mode of transportation is equally likely (since we do not know its travel habits) :
P(L)= probability of taking the bicycle * probability of being late if he takes the bicycle + probability of taking the car* probability of being late if he takes the car + probability of taking the bus* probability of being late if he takes the bus +probability of taking the train* probability of being late if he takes the train = 1/4 * 0.75 + 1/4 * 0.43 + 1/4 * 0.15 + 1/4 * 0.05 = 0.345
then we can use the theorem of Bayes for conditional probability. Thus defining the event C= Bob takes the car , we have
P(C/L)= P(C∩L)/P(L) = 1/4 * 0.43 /0.345 = 0.311 (31.1%)
where
P(C∩L)= probability of taking the car and being late
P(C/L)= probability that Bob had taken the car given that he is late