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2 years ago

1 point

Mathematics

1 answer:

GenaCL600 [577]2 years ago

8 0

Answer:

O V=202-6x; $94

Step-by-step explanation:

202 needs to be placed before the 6, eliminating options 1 and 2. It can't be option 4 because thats more than 202, leaving us with option 3. Check you answer by replacing x with 18. O V=202-6(18) ->O V=202-108 -> 202-108=$94.

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There are 12 inches (in.) in 1 foot (ft). Which expression can be used to find the number of inches in 2.5 feet?

Tasya [4]

I think the correct answer is c

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3 years ago

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Solve the equation 58 - 10x ≤ 20 + 9x

drek231 [11]

Answer:

x≥2

Step-by-step explanation:

First, write out the equation as you have it:

$58-10x\leq20+9x$

Then, add $10x$ to both sides:

$58-10x+10x\leq20+9x+10x\\58\leq20+19x$

Next, subtract $20$ from both sides:

$58-20\leq20-20+19x\\38\leq19x$

Finally, divide both sides by $19$ :

$\frac{38}{19}\leq\frac{19x}{19}\\2\leq x$

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Therefore: the answer to this inequality/equation is: x≥2

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3 years ago

*Asymptotes*<br> g(x) =2x+1/x-3 <br><br> Give the domain and x and y intercepts

Nataly [62]

Answer: Assuming the function is $g(x)=\frac{2x+1}{x-3}$ :

The x-intercept is $(\frac{-1}{2},0)$ .

The y-intercept is $(0,\frac{-1}{3})$ .

The horizontal asymptote is $y=2$ .

The vertical asymptote is $x=3$ .

Step-by-step explanation:

I'm going to assume the function is: $g(x)=\frac{2x+1}{x-3}$ and not $g(x)=2x+\frac{1}{x}-3$ .

So we are looking at $g(x)=\frac{2x+1}{x-3}$ .

The x-intercept is when y is 0 (when g(x) is 0).

Replace g(x) with 0.

$0=\frac{2x+1}{x-3}$

A fraction is only 0 when it's numerator is 0. You are really just solving:

$0=2x+1$

Subtract 1 on both sides:

$-1=2x$

Divide both sides by 2:

$\frac{-1}{2}=x$

The x-intercept is $(\frac{-1}{2},0)$ .

The y-intercept is when x is 0.

Replace x with 0.

$g(0)=\frac{2(0)+1}{0-3}$

$y=\frac{2(0)+1}{0-3}$

$y=\frac{0+1}{-3}$

$y=\frac{1}{-3}$

$y=-\frac{1}{3}$ .

The y-intercept is $(0,\frac{-1}{3})$ .

The vertical asymptote is when the denominator is 0 without making the top 0 also.

So the deliminator is 0 when x-3=0.

Solve x-3=0.

Add 3 on both sides:

x=3

Plugging 3 into the top gives 2(3)+1=6+1=7.

So we have a vertical asymptote at x=3.

Now let's look at the horizontal asymptote.

I could tell you if the degrees match that the horizontal asymptote is just the leading coefficient of the top over the leading coefficient of the bottom which means are horizontal asymptote is $y=\frac{2}{1}$ . After simplifying you could just say the horizontal asymptote is $y=2$ .