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irina [24]
3 years ago
12

A student is hit with a 1 kg pumpkin pie. The kinetic energy of the pie 32 J. What was the speed of the pie?

Physics
1 answer:
Zarrin [17]3 years ago
5 0

1000 \div 33
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What is pulling force expansion​
Aloiza [94]

Answer:

physical cosmology, the Big Rip is a hypothetical cosmological model concerning the ultimate fate of the universe, in which the matter of the universe, from stars and galaxies to atoms and subatomic particles, and even spacetime itself, is progressively torn apart by the expansion of the universe at a certain time

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2 years ago
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An electric motor is rated at 900 W. How much force does it apply when moving
brilliants [131]
<h3>Answer:  7.74 newtons</h3>

========================================

Steps Shown:

Work = Force*Displacement

Power = Work/Time

Power = (Force*Displacement)/Time

900 W = (F*1000 m)/(8.6 sec)

900 = (F*1000)/8.6

900*8.6 = 1000F

7740 = 1000F

1000F = 7740

F = 7740/1000

F = 7.74 newtons

6 0
2 years ago
Electron kinetic energies are often measured in units of electron-volts (1 eV 1.6 x 10-19 J), which is the kinetic energy of an
PolarNik [594]

Answer:

4.1 eV

Explanation:

Kinetic energy, K = 0.8 eV = 0.8 x 1.6 x 10^-19 J = 1.28 x 10^-19 J

wavelength, λ = 253.5 nm = 253.5 x 10^-9 m

According to the Einstein energy equation

E = W_{o}+K

Where, E be the energy incident, Wo is the work function and K is the kinetic energy.

h = 6.634 x 10^-34 Js

c = 3 x 10^8 m/s

E=\frac{hc}{\lambda }=\frac{6.634 \times 10^{-34} \times 3 \times 10^{8}}{253.5\times 10^{-9}}=7.85 \times 10^{-19} J

So, the work function, Wo = E - K

Wo = 7.85 x 10^-19 - 1.28 x 10^-19

Wo = 6.57 x 10^-19 J

Wo = 4.1 eV

Thus, the work function of the metal is 4.1 eV.

5 0
3 years ago
a. Define Valency. b. Write the symbol and valency of the following : (i) Oxygen (ii) potassium 7. a. Magnesium burns in Oxygen
sweet-ann [11.9K]

Answer:

Oxygen-Symbol-O Potassium Symbol-K

6 0
3 years ago
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If the tension in the rope is 160 n, how much work does the rope do on the skier during a forward displacement of 270 m?
Lunna [17]

If the tension in the rope is 160 n, - 43200 J work doen by the rope on the skier during a forward displacement of 270 m.

Given,

Tension force in the rope is (T) = 160 N

Displacement of the skier (S) = 270 m

The displacement takes place in forward direction while the direction of the tension in the rope is opposite to it.

Therefore, work done by the rope on  the skier is,

   W=T.S

⇒W=270*160*cos\pi \\W=-43200 J

Hence work done by the rope is - 43200 J.

Learn more about force problems on

brainly.com/question/26850893

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8 0
2 years ago
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