A 20 cm square frame that can rotate about the 00' axis is placed in a homogeneous magnetic field with 0.5T induction directed v
ertically downwards.
a) Draw vectors of forces acting on the sides of the frame.
b) calculate the values of these forces and the resultant force acting on the frame.
c) calculate the torque of the frame.
a) Draw vectors of forces acting on the sides of the frame.
b) calculate the values of these forces and the resultant force acting on the frame.
c) calculate the torque of the frame.
1 answer:
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Answer:
α = 13.7 rad / s²
Explanation:
Let's use Newton's second law for rotational motion
∑ τ = I α
we will assume that the counterclockwise turns are positive
F₁ 0 + F₂ R₂ - F₃ R₃ = I α
give us the cylinder moment of inertia
I = ½ M R₂²
α = (F₂ R₂ - F₃ R₃)
let's calculate
α = (24 0.22 - 13 0.10) 2/12 0.22²
α = 13.7 rad / s²
So, <u>the value of the work is approximately 84.65 J</u>.
<h2>Introduction</h2>Hi ! Here I will help you to discuss the subject about work that caused by force in amount value of angle. Work is affected by the force and displacement.
- If related to the magnitude of the force, the amount of work will be proportional to the magnitude of the applied force. Thats mean, if the value of the force that applied on it is greater, then the value of the work will be greater.
- If related to the magnitude of shift, the amount of work will be proportional to the magnitude of shift of object. Thats mean, if the value of the shift on it is greater, then the value of the work will be greater.
The work done by a moving object can be expressed in the equation:
If the Angle Is Ignored
If the Angle Effect on Work
With the following condition:
- W = work that done by object (J)
- F = force that applied (N)
- s = shift or distance (m)
= angle of elevation (°)
We know that :
- F = force that applied =
N
- s = shift or distance = 84.9 m
What was asked ?
- W = work that done by object = ... J
Step by step :
So, the value of the work is approximately 84.65 J.
Answer:
θ=142.9°
Explanation:
d=1 *r
angle ϕ= 37.1°
the line connecting pebble and target should be tangent to a circle so
cos(180-ϕ-θ)==
∴ θ=180-ϕ-
θ= 180-37.1-0
θ=142.9°
