Answer:
Based on the properties electrically charged particles, we have that unlike charges attract and like charges repel each other. In order for proper application of an electrostatically negatively charged paint to be properly applied on the metal body surface of a vehicle, require that for attraction, the surface of the vehicle should be grounded and positively charged so as to effectively attract the negatively charged paint particles as it exits the nozzle, to form a strong attachment with the positively charged surface of the vehicle
Explanation:
<em>Your answer is:</em>
<em>c) </em><u><em>20°</em></u>
<em />
<em>∝ </em><em>Sidhdi</em>
Answer:
Approximately 
(assuming that 
.)
Explanation:
Let 
denote the force that this spring exerts on the object. Let 
denote the displacement of this spring from the equilibrium position.
By Hooke's Law, the spring constant 
of this spring would ensure that 
.
Note that the mass of the object attached to this spring is 
. Thus, the weight of this object would be 
.
Assuming that this object is not moving, the spring would need to exert an upward force of the same magnitude on the object. Thus, 
.
The spring in this question was stretched downward from its equilibrium by:
.
(Note that is negative since this displacement points downwards.)
Rearrange Hooke's Law to find in terms of and :
.
Answer:
Answer explained below
Explanation:
(a) The rays are diverging near the lens. They change the direction when they passed through the converging lens
(b) If the light rays don't bend they will move away from the optical (principal axis) as the other waves are moving.
(c) If we decrease the distance between lens and light source, most of the rays diverge and no ray converges on the screen even after passing through the lens. Here is a screenshot.
The distance that would be accumulated during the journey is 2.5 meters
The parameters given in the question are written below;
average speed= 5 km/hr
time = 30 minutes
convert 30 minutes to hours
= 30/60
= 0.5 hours
Distance-= speed × time
= 5 × 0.5
= 2.5 meters
Hence the distance of the entire journey is 2.5 meters
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