Given that,
Mass of a boy = 50 kg
The coefficient of static friction = 0.68
To find,
Let us assume we need to find the maximum static friction between the boy and the ground.
Solution,
The formula for the maximum static friction between the two objects is given by :
Where
N is normal force
Substitute all the values,
Therefore, the maximum static friction between the boy and the ground is 340 N.
We have that Since Cart A spends t=77.5secs and Cart B spends t=50sec
Therefore
The Cart A wins the Race and by 25.5( 77.7-50)secs
From the question we are told
For Cart A
Generally the equation for the Velocity is mathematically given as
For Cart B
Generally the Newtons equation for the Motion is mathematically given as
Since
Cart A spends t=77.5secs and Cart B spends t=50sec
Therefore
The Cart A wins the Race and by 25.5( 77.7-50)secs
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By Newton's second law, we have
So, in order to give a 0.15kg body an acceleration of 40m/s^2, you need a force of