Question

A two-dimensional object placed in the xy-plane has three forces acting on it: a force of 3.0 n along the x-axis acting at a point (3 m, 4 m); a force of 2.0 n along the y-axis acting at (-2 m, 5 m); and a force of 5 n in the negative x direction acting at (-2 m, -3 m). what is the net torque about the point (-1 m, 1 m)?

Answer 1

the net torque about the point (-1 m, 1 m) is 4 N-m.

The resultant force acting on the object is calculated as

R^2=(-5+3)^2+2^2=2.82 N

Distance of the point from the resultant force

d^2=(-1)^2+1^2=1.414

The net torque acting on the point (-1 m, 1 m) is

T=2.82×1.41=3.98 N-m