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11111nata11111 [884]
3 years ago
6

Hi can you help me with this please?

Physics
1 answer:
bagirrra123 [75]3 years ago
5 0

Answer:

4s

Explanation:

My assumption would be 4s since 25 going into 100 would be 4? hope that helped..

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When pressing the accelerator on a car, the ___________ energy of the fuel is transformed into the _____________ energy that mak
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#3: a container has the dimensions of 30 cm x 50 mm x 0.2 m. the density of its contents is 2.5 g/cm3. what is the mass of the s
WARRIOR [948]
Good afternoon!

We calculate the volume of the container in cm³. To do that, we must put the units in cm:

30 cm → 30 cm
50 mm → 5 cm
0.2 m → 20 cm

The volume is:

V = 30 . 5 . 20

V = 3000 cm³

Now, we calculate the mas with the formula:

m = dV

m = 2.5 · 3000

m = 7500 g

Dividing by 1000, we have the mass in kg:


m = 7.5 kg
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No.  A mirror works because of reflection.

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⦁ A car going 50 m/s is brought to rest in a distance of 20.0 m as it strikes a pile of dirt. How large an average force is exer
gtnhenbr [62]

Answer:

the average force exerted by seatbelts on the passenger is 5625 N.

Explanation:

Given;

initial velocity of the car, u = 50 m/s

distance traveled by the car, s = 20 m

final velocity of the after coming to rest, v = 0

mass of the passenger, m = 90 kg

Determine the acceleration of the car as it hit the pile of dirt;

v² = u² + 2as

0 = 50² + (2 x 20)a

0 = 2500 + 40a

40a = -2500

a = -2500/40

a = -62.5 m/s²

The deceleration of the car is 62.5 m/s²

The force exerted on the passenger by the backward action of the car is calculated as follows;

F = ma

F = 90 x 62.5

F = 5625 N

Therefore, the average force exerted by seatbelts on the passenger is 5625 N.

8 0
3 years ago
A microphone is attached to a spring that is suspended from the ceiling, as the drawing indicates. Directly below on the floor i
svet-max [94.6K]

Answer:

0.261\ \text{m}

Explanation:

\Delta f = Change in frequency = 2.1 Hz

f = Frequency of source of sound = 440 Hz

v_m= Maximum of the microphone

v = Speed of sound = 343 m/s

T = Time period = 2 s

We have the relation

\Delta f=2f\dfrac{v_m}{v}\\\Rightarrow v_m=\dfrac{\Delta fv}{2f}\\\Rightarrow v_m=\dfrac{2.1\times 343}{2\times 440}\\\Rightarrow v_m=0.8185\ \text{m/s}

Amplitude is given by

A=\dfrac{v_m T}{2\pi}\\\Rightarrow A=\dfrac{0.8185\times 2}{2\pi}\\\Rightarrow A=0.261\ \text{m}

The amplitude of the simple harmonic motion is 0.261\ \text{m}.

4 0
3 years ago
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