Complete Question: A horse pulls a cart along a flat road. Consider the following four forces that arise in this situation. (1) the force of the horse pulling on the cart (2) the force of the cart pulling on the horse (3) the force of the horse pushing on the road (4) the force of the road pushing on the horse Suppose that the horse and cart have started from rest; and as time goes on, their speed increases in the same direction. Which one of the following conclusions is correct concerning the magnitudes of the forces mentioned above?
A) Force 1 exceeds force 2.
B) Force 2 is less than force 3.
C) Force 2 exceeds force 4.
D) Force 3 exceeds force 4.
E) Forces 1 and 2 cannot have equal magnitudes.
Answer: B) Force 2 is less than force 3.
Explanation: From the given four forces to be considered, Force 2 is less than Force 3 is correct option.
After evaluating the forces one by one. Force 3 and Force 4 are the same, both have equal magnitude.
And Force 3 is greater than Force 2, i.e., the force of the horse pushing on the road is much higher than the cart pulling the horse. Hence, more forces is required to pull the cart while on the road towards forward direction.
More so, the force of the road pushing on the horse is greater than the force of the cart pulling on the horse.
Answer:
1.86 x 10^8 m/s
Explanation:
n = 1.61
The formula for the refractive index is given by
n = speed of light in vacuum / speed of light in material
n = c / v
v = c / n
v = (3 x 10^8) / 1.61
v = 1.86 x 10^8 m/s
What is the magnitude of force required to accelerate a car of mass 1.7 × 10³ kg by 4.75 m/s²
Answer:
F = 8.075 N
Explanation:
Formula for force is;
F = ma
Where;
m is mass
a is acceleration
F = 1.7 × 10³ × 4.75
F = 8.075 N
Answer:
The deviation of a mirror is equal to twice the angle of incidence.The total angle between the straight-line path and the reflected ray is twice the angle of incidence. This is called the deviation of the light and measures the angle at which the light has strayed from its initial straight-line path.
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Answer:
we learned that an object that is vibrating is acted upon by a restoring force. The restoring force causes the vibrating object to slow down as it moves away from the equilibrium position and to speed up as it approaches the equilibrium position. It is this restoring force that is responsible for the vibration. So what forces act upon a pendulum bob? And what is the restoring force for a pendulum? There are two dominant forces acting upon a pendulum bob at all times during the course of its motion. There is the force of gravity that acts downward upon the bob. It results from the Earth's mass attracting the mass of the bob. And there is a tension force acting upward and towards the pivot point of the pendulum. The tension force results from the string pulling upon the bob of the pendulum. In our discussion, we will ignore the influence of air resistance - a third force that always opposes the motion of the bob as it swings to and fro. The air resistance force is relatively weak compared to the two dominant forces.
The gravity force is highly predictable; it is always in the same direction (down) and always of the same magnitude - mass*9.8 N/kg. The tension force is considerably less predictable. Both its direction and its magnitude change as the bob swings to and fro. The direction of the tension force is always towards the pivot point. So as the bob swings to the left of its equilibrium position, the tension force is at an angle - directed upwards and to the right. And as the bob swings to the right of its equilibrium position, the tension is directed upwards and to the left. The diagram below depicts the direction of these two forces at five different positions over the course of the pendulum's path.
that's what I know so far
