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liubo4ka [24]
3 years ago
8

Name some advantages and disadvantages of the graphing method and the algebraic method when determining solutions for linear fun

ctions
Mathematics
1 answer:
Vika [28.1K]3 years ago
8 0
<span>The algebraic method is more useful when working with numbers and trying to solve for different things. These things could be x and y intercepts or points of intersection with other lines. Yet it doesn't offer the visual aid of graphs. The graphing method is useful because you can see where things intercept. It can check the answer of the algebraic function by easily looking at the graph and seeing if the answer makes sense. Of course the graphing method may not be as easy to see exact, small numbers as compared with the algebraic method.</span>
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How do you do these questions?
Alika [10]

Answer:

a) - 7 dollars

b) 24.30 dollars

c) - 5 dollars

Step-by-step explanation:

b) 27 / 10%

Divide 27 by 10/100 by multiplying 27 by the reciprocal of 10/100.

27 x 100/10

Multiply 27 and 100 to get 2700.

2700/10

Divide 2700 by 10 to get 270.

270

Divide 270 by 100 to get 2.7

Subtract 27.00 - 2.7 = 24.30

24.30

4 0
3 years ago
What is 2.50x + 4x = 39
34kurt
2.5x + 4x = 39
6.5x = 39
x = 39 / 6.5
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3 years ago
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faltersainse [42]

Answer:

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Step-by-step explanation:

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5 0
3 years ago
Given that sin theta = 1/4, 0→theta→π/2, what<br>. what is the exact value of cos 8?​
natali 33 [55]
<h3>Answer: Choice B \frac{\sqrt{15}}{4}</h3>

===========================================================

Work Shown:

Angle theta is between 0 and pi/2, so this angle is in quadrant Q1.

Square both sides of the given equation

\sin \theta = \frac{1}{4}\\\\\sin^2 \theta = \left(\frac{1}{4}\right)^2\\\\\sin^2 \theta = \frac{1}{16}

Then use the pythagorean trig identity to get

\sin^2 \theta + \cos^2 \theta = 1\\\\\cos^2 \theta = 1-\sin^2 \theta\\\\\cos \theta = \sqrt{1-\sin^2 \theta} \ \ \ \text{cosine is positive in Q1}\\\\\cos \theta = \sqrt{1-\frac{1}{16}}\\\\\cos \theta = \sqrt{\frac{16}{16}-\frac{1}{16}}\\\\\cos \theta = \sqrt{\frac{16-1}{16}}\\\\\cos \theta = \sqrt{\frac{15}{16}}\\\\\cos \theta = \frac{\sqrt{15}}{\sqrt{16}}\\\\\cos \theta = \frac{\sqrt{15}}{4}\\\\

3 0
3 years ago
On a certain day the exchange rate was 60 U.S dollars for 50 euro. How many U.S dollars were 70 euro worth that day?
Bezzdna [24]
70 euros in u.s dollars is $60
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3 years ago
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