Answer:
6t = -21
Step-by-step explanation:
3t-7 = 5t simplifies by subtracting 5t on both sides, then adding 7 on both sides:
3t -5t -7 +7 = 5t-5t+7
-2t = 7
t = -7/2
Then 6t = 6*-7/2 = -21
0 = 0
Simplifying
7x + -11 = 5(x + -2) + 2x + -1
Reorder the terms:
-11 + 7x = 5(x + -2) + 2x + -1
Reorder the terms:
-11 + 7x = 5(-2 + x) + 2x + -1
-11 + 7x = (-2 * 5 + x * 5) + 2x + -1
-11 + 7x = (-10 + 5x) + 2x + -1
Reorder the terms:
-11 + 7x = -10 + -1 + 5x + 2x
Combine like terms: -10 + -1 = -11
-11 + 7x = -11 + 5x + 2x
Combine like terms: 5x + 2x = 7x
-11 + 7x = -11 + 7x
Add '11' to each side of the equation.
-11 + 11 + 7x = -11 + 11 + 7x
Combine like terms: -11 + 11 = 0
0 + 7x = -11 + 11 + 7x
7x = -11 + 11 + 7x
Combine like terms: -11 + 11 = 0
7x = 0 + 7x
7x = 7x
Add '-7x' to each side of the equation.
7x + -7x = 7x + -7x
Combine like terms: 7x + -7x = 0
0 = 7x + -7x
Combine like terms: 7x + -7x = 0
0 = 0
Solving
0 = 0
<h3>
Answer:</h3>
see attached for a graph
domain and range: all real numbers
<h3>
Step-by-step explanation:</h3>
The function is written in slope-intercept form, showing that it has a slope of -3 and a y-intercept of +7. The y-intercept (0, 7) is a point on the line, as is a point 1 unit to the right and down 3 units, (1, 4).
The graph will be the line through these two points.
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As with any odd-degree polynomial function, both domain and range are all real numbers: (-∞, ∞).
Wouldn’t it be 0, as that’s when their values are both equal to each other, making the equation true?