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Lesechka [4]
2 years ago
10

Which equation is correct regarding the measure of ∠1?

Mathematics
2 answers:
ratelena [41]2 years ago
7 0

Answer:

C.  m∠1 = 1/2 (b – d)

Step-by-step explanation:

(just took test on edg and got it right)

german2 years ago
3 0

Answer:

C

Step-by-step explanation:

I just did it on edge

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Which sequence follows the rule an =an–1 + 7?
Akimi4 [234]

Answer:

A

Step-by-step explanation:

using the rule : a_{n} = a_{n-1} + 7

sequence A with a₁ = 11

a₂ = a₁ + 7 = 11 + 7 = 18

a₃ = a₂ + 7 = 18 + 7 = 25

a₄ = a₃ + 7 = 25 + 7 = 32

sequence A is generated using the rule

sequence B with a₁ = 17

a₂ = a₁ + 7 = 17 + 7 = 24

a₃ = a₂ + 7 = 24 + 7 = 31

a₄ = a₃ + 7 = 31 + 7 = 38

sequence B is not generated using the rule

sequence C with a₁ = - 15

a₂ = - 15 + 7 = - 8

a₃ = a₂ + 7 = - 8 + 7 = - 1

a₄ = a₃ + 7 = - 1 + 7 = 6

sequence C is not generated using the rule

sequence D with a₁ = - 9

a₂ = a₁ + 7 = - 9 + 7 = - 2

a₃ = a₂ + 7 = - 2 + 7 = 5

a₄ = a₃ + 7 = 5 + 7 = 12

sequence D is not generated using the rule



7 0
2 years ago
Two wrongs and One right: vertical angles. Please help only 2-3 questions
luda_lava [24]

Answer:

Solution one is correct and solution 2 and 3 are incorrect

Step-by-step explanation:

You simply make an equation because for vertical angles 2 angles that are across from each other have the same value (in this case 2x+30 and 5x-36.)

The equation: 2x+30=5x-36---->3x=66----> x=22

Solution 1 is correct.

Hope this helped!

3 0
3 years ago
Read 2 more answers
Given the equation y=x2 + 3, how will the graph change if the value of A is doubled?
elena-s [515]
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6 0
3 years ago
Find two rational expressions a / b and c / d that produce the result x − 1 / x2 when using the following operations. Answers
Mars2501 [29]

Answer:

a) Let \frac{a}{b}=\frac{-1}{x^2}, \text{ and } \frac{c}{d}=\frac{1}{x}.

Observe that

\frac{a}{b}+\frac{c}{d}=\frac{-1}{x^2}+\frac{1}{x}=\frac{-x+x^2}{x^3}=\frac{x(x-1)}{xx^2}=\frac{x-1}{x^2}

b)

Let \frac{a}{b}=\frac{1}{x}, \text{ and } \frac{c}{d}=\frac{1}{x^2}.

Observe that

\frac{a}{b}-\frac{c}{d}=\frac{1}{x}-\frac{1}{x^2}=\frac{x^2-x}{x^3}=\frac{x(x-1)}{xx^2}=\frac{x-1}{x^2}

c)

Let \frac{a}{b}=\frac{x-1}{x}, \text{ and } \frac{c}{d}=\frac{1}{x}.

Observe that

\frac{a}{b}*\frac{c}{d}=\frac{x-1}{x}*\frac{1}{x}=\frac{(x-1)1}{x*x}=\frac{x-1}{x^2}

d)

Let \frac{a}{b}=\frac{x-1}{x}, \text{ and } \frac{c}{d}=\frac{x}{1}.

Observe that

\frac{a}{b}\div\frac{c}{d}=\frac{x-1}{x}\div\frac{x}{1}=\frac{x-1}{x}*\frac{1}{x}=\frac{x-1}{x^2}

3 0
3 years ago
Hey i was wondering can i move +7 from inside the absolute value in the left side to -7 outside the absolute value on the right
pashok25 [27]

Answer:

  • A) Zero

Step-by-step explanation:

<u>Given equation:</u>

  • |x + 7| = - 4

The left side is absolute value, we know it is zero or positive value but never negative.

The right side is negative so the equation can't have solutions as we have contradiction above.

5 0
2 years ago
Read 2 more answers
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