Answer: Un alambre de acero de 1.5 m se estira 2.0 mm con fuerza F. El diámetro del alambre de acero es 4.0 mm. El módulo de Young del acero es 2.0 x 1011 Nm-2. Determine la fuerza F aplicada sobre el alambre.
Step-by-step explanation:
Answer:
d. about $1.65 billion
Step-by-step explanation:
$1.8 billion × .916 = $1.6488 billion, or about $1.65 billion
Answer:
30%. Based on the given conditions, formulate: 12/40 Cross out the common factor: 3/10 Multiply a number.
Step-by-step explanation:
Answer:
1/500
Step-by-step explanation:
Step-by-step explanation:
4x -20 + 3x +12 = 90
7x -8 = 90
7x = 98
x = 14
Angle F: 4(14) -20 = 36
Angle E: 3(14)+12= 54
Angle G : 90