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jekas [21]
4 years ago
10

What visible wavelengths of light are strongly reflected from a 390-nm-thick soap bubble?

Physics
1 answer:
DiKsa [7]4 years ago
6 0

Answer:

So visible wavelength which is possible here is

416 nm and 693.3 nm

Explanation:

As we know that for normal incidence of light the path difference of the reflected ray is given as

2\mu t + \frac{\lambda}{2} = \Delta x

so here we can say that for maximum intensity condition we will have

\Delta x = N\lambda

so we have

2\mu t + \frac{\lambda}{2} = N\lambda

now for visible wavelength we have

for N = 1

2\mu t = \frac{\lambda}{2}

\lambda = 4\mu t

\lambda = 4(\frac{4}{3})(390 nm)

\lambda = 2080 nm

for N = 2

\lambda = \frac{4\mu t}{3}

\lambda = \frac{4(\frac{4}{3})(390 nm)}{3}

\lambda = 693.3 nm

for N = 3

\lambda = \frac{4\mu t}{5}

\lambda = \frac{4(\frac{4}{3})(390 nm)}{5}

\lambda = 416 nm

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2 meters per second is the answer
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4 years ago
What is the wavelength of the electromagnetic radiation needed to eject electrons from a metal?
LuckyWell [14K]

Answer:

λ = hc/(eV + hf_{0})

Explanation:

Let the work function of the metal = ∅

the kinetic energy with which the electrons are ejected = E

the energy of the incident electromagnetic wave = hf

Then, we know that the kinetic energy of the emitted electron will be

E = hf - ∅

because the energy of the incident electromagnetic radiation must exceed the work function for electrons to be ejected.

This means that the energy of the incident e-m wave can be written as

hf = E + ∅

also, we know that the kinetic energy of the emitted electron E = eV

and the work function ∅ = hf_{0}

we can they combine all equations to give

hf = eV + hf_{0}

we know that f = c/λ

substituting, we have

hc/λ = eV + hf_{0}

λ = hc/(eV + hf_{0})    This is the wavelength of the e-m radiation needed to eject electrons from a metal.

where

λ is the wavelength of the e-m radiation

h is the Planck's constant = 6.63 x 10^-34 m^2 kg/s

c is the speed of e-m radiations in a vacuum = 3 x 10^8 m/s

e is the charge on an electron

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8 0
3 years ago
Which phrase describes an electromagnetic wave
Viefleur [7K]

Answer:

<u>a transverse wave consisting of changing electric fields and changing magnetic fields.</u>

Explanation:

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All electromagnetic waves propagate at the same speed in vacuum. This speed is approximately 3.0 × 10⁸ m/s. Which is generally referred as the speed of light, but it is the same constant speed of any electromagnetic wave in the vacuum, c.

In general, waves transfer energy when they travel, but only electromagnetic waves can travel in vacuum. The waves that cannot travel in vacuum are named mechanical waves (they need a medium to travel).

There are two types of waves depending on how they propagate: transverse waves and longitudinal waves. The transverse waves travel perperdiculary to the direcction of the vibration, while longitudinal waves travel parallel to the direction of the vibration.

The classical example of transverse waves is a rope that oscilates up and down. The classical example of  longitudinal waves is a spring that you pull and push by an end and so it  moves forward and back. Sound is also a longitudinal wave.

4 0
2 years ago
462.3 cm - 25.74 cm
Murrr4er [49]

Answer:

436.56 centimeters

Explanation:

heart this! My answer is correct, I search it.

8 0
3 years ago
(7) A 2500 lbm car moving at 25 mi/hr is accelerated at a constant rate of 15 ft/s2 up to a speed of 50 mi/hr. What is the force
balandron [24]

Answer:

The  force is  F =  1164.6\  lbf

The time is   \Delta t =  2.44 \  s

Explanation:

From the question we are told that

  The  mass of the car is  m  =  2500 \ lbm

   The  initial velocity of the car is u  =  25 \ mi/hr

   The final  velocity of the car is  v  =  50 \  mi/hr

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Generally the acceleration is mathematically represented as

      a =  \frac{v-u}{\Delta t}

=>   36818.2 =  \frac{50 - 25 }{ \Delta t}

=>   t = 0.000679 \  hr

converting to seconds

       \Delta t =  0.0000679 *  3600

=>     \Delta t =  2.44 \  s

Generally the force is mathematically represented as

        F  =  m * a

=>      F  =  2500 *  15

=>      F  =  37500 \ \frac{lbm *  ft}{s^2}

Now converting to foot-pound-second we have  

         F =  \frac{37500}{32.2}

=>        F =  1164.6\  lbf

7 0
3 years ago
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