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katovenus [111]
3 years ago
9

A rock rolls down a steep hill. Its intial velocity is 1 meter per second. By the time it reaches the bottom of the hill 30 seco

nds later. Its velocity is 7 meters per second. What is the acceleration of the rock
Physics
1 answer:
Andru [333]3 years ago
7 0
2 meters per second is the answer
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The unit used to measure electric current is the ampere (A). Now, assume that the current delivered at a wall socket reaches the
pav-90 [236]

Answer:

T = 0.017s

Explanation:

period is the time it takes a particle to make one oscillation

An electric current is periodic in nature

The current reaches 3.8A  ten times.  

So there must have been 10 cycles (10 periods) in 0.17s.   let 'T'  be the period:

T=\frac{t}{n}

t is the total time interval

n is the number of oscillations

T=\frac{0.17}{10}

10T = 0.17

T = 0.17/10 = 0.017s

8 0
3 years ago
Two point charges, 1.8 pC and −1.8 pC, are separated by 7 µm. What is the dipole moment of this pair of charges?
Salsk061 [2.6K]

Answer: 12,600,000Cm

Explanation:

From the data's;

Charges(q) = 1.8 PC equal to 1.8 x 10^¹²C

Distance = 7 micrometer, is equal to 0.0000070m

From the equation of electric dipole moment, p= q x d, where q= charge, d=distance and p is the dipole moment.

Then we have 1.8x10^¹² x 0.0000070= 12,600,000Cm

NB: The charges are identical.

3 0
3 years ago
What the kinetic Energy of 80kg<br> object this is Moving with a Speed<br> of 23 m/s
Katyanochek1 [597]

Explanation:

Kinetic Energy Formula = ½mv²

  • ½×800kg×(23m/s)²
  • 400kg×529m²/s²
  • 211600 kg•m²/s²
  • 211700 joule Answer

4 0
2 years ago
Why is it warmer near the equator than near the poles?
maw [93]
The equator is warmer than the poles because the equator is closer to the sun. In other words, the sun is overhead the equator, which is a result of the Earth's curvature. 
3 0
3 years ago
The electron affinity of thulium has been measured by a technique known as laser photodetachment electron spectroscopy. In this
antoniya [11.8K]

Answer:

ΔE = 1.031 eV

Explanation:

For this exercise let's calculate the energy of the photons using Planck's equation

          E = h f

wavelength and frequency are related

         c = λ f

         f = c /λ

let's substitute

         E = h c /λ

let's calculate

         E = 6.63 10⁻³⁴ 3 10⁸/1064 10⁻⁹

         E = 1.869 10⁻¹⁹ J

let's reduce to eV

         E = 1.869 10⁻¹⁹ J (1 eV / 1.6 10⁻¹⁹ J)

        E = 1.168 eV

therefore the electron affinity is

         ΔE = E - 0.137

         ΔE = 1.168 - 0.137

         ΔE = 1.031 eV

3 0
3 years ago
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