All categories

2 years ago

Which phrase describes an electromagnetic wave

Physics

1 answer:

Viefleur [7K]2 years ago

4 0

Answer:

<u>a transverse wave consisting of changing electric fields and changing magnetic fields.</u>

Explanation:

An electromagnetic wave is a wave generated by the vibration of perpendicular electric and magnetic fields, which may progate through vacuum (empty space) or a material medium.

All electromagnetic waves propagate at the same speed in vacuum. This speed is approximately 3.0 × 10⁸ m/s. Which is generally referred as the speed of light, but it is the same constant speed of any electromagnetic wave in the vacuum, c.

In general, waves transfer energy when they travel, but only electromagnetic waves can travel in vacuum. The waves that cannot travel in vacuum are named mechanical waves (they need a medium to travel).

There are two types of waves depending on how they propagate: transverse waves and longitudinal waves. The transverse waves travel perperdiculary to the direcction of the vibration, while longitudinal waves travel parallel to the direction of the vibration.

The classical example of transverse waves is a rope that oscilates up and down. The classical example of longitudinal waves is a spring that you pull and push by an end and so it moves forward and back. Sound is also a longitudinal wave.

You might be interested in

Find the components of vtot along the x and y axes in Figure 3.25, where = 23.0° and vtot = 7.56 m/s.

Romashka [77]

The component of the total velocity in the x - direction is 6.96 m/s.

The component of the total velocity in the y - direction is 2.95 m/s.

<h3>Component of the velocity in x direction </h3>

The component of the total velocity in the x - direction is calculated as follows;

v(x) = vtot cosθ

where;

vtot is total velocity
v(x) is velocity in x direction

v(x) = 7.56 x cos(23)

v(x) = 6.96 m/s

<h3>Component of the velocity in y - direction</h3>

v(y) = vtot sinθ

v(y) = 7.56 x sin(23)

v(y) = 2.95 m/s

Learn more about component velocity here: brainly.com/question/24681896

#SPJ1

7 0

2 years ago

Which chemical reaction involving water is a decomposition reaction (breaking up) and which is a synthesis (building up) reactio

vichka [17]

Water breaking down into hydrogen and oxygen is a decomposition reaction.
<span>Hydrogen and oxygen combining to form water is a synthesis reaction.</span>

5 0

3 years ago

Read 2 more answers

In the diagram, q1 and q2 are both +5.00*10^-8 C. What is the electric field at point P? Include a + or - sign to indicate the d

Damm [24]

Answer:

1389.1

Explanation:

6 0

3 years ago

A sled of mass 50 kg is pulled along a snow-covered, flat ground. The static friction coefficient is 0.3 and the kinetic frictio

Diano4ka-milaya [45]

Answer:

a) We kindly invite you to see below the Free Body Diagram of the forces acting on the sled.

b) The weight of the sled is 490.35 newtons.

c) A force of 147.105 newtons is needed to start the sled moving.

d) A force of 49.035 newtons is needed to keep the sled moving at a constant velocity.

Explanation:

a) We kindly invite you to see below the Free Body Diagram of the forces acting on the sled. All forces are listed:

$F$ - External force exerted on the sled, measured in newtons.

$f$ - Friction force, measured in newtons.

$N$ - Normal force from the ground on the mass, measured in newtons.

$W$ - Weight, measured in newtons.

b) The weight of the sled is determined by the following formula:

$W = m\cdot g$ (1)

Where:

$m$ - Mass, measured in kilograms.

$g$ - Gravitational acceleration, measured in meters per square second.

If we know that $m = 50\,kg$ and $g = 9.807\,\frac{m}{s^{2}}$ , the weight of the sled is:

$W = (50\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)$

$W = 490.35\,N$

The weight of the sled is 490.35 newtons.

c) The minimum force needed to start the sled moving on the horizontal ground is:

$F_{min,s} = \mu_{s}\cdot W$ (2)

Where:

$\mu_{s}$ - Static coefficient of friction, dimensionless.

$W$ - Weight of the sled, measured in newtons.

If we know that $\mu_{s} = 0.3$ and $W = 490.35\,N$ , then the force needed to start the sled moving is:

$F_{min,s} = 0.3\cdot (490.35\,N)$

$F_{min,s} = 147.105\,N$

A force of 147.105 newtons is needed to start the sled moving.

d) The minimum force needed to keep the sled moving at constant velocity is:

$F_{min,k} = \mu_{k}\cdot W$ (3)

Where $\mu_{k}$ is the kinetic coefficient of friction, dimensionless.

If we know that $\mu_{k} = 0.1$ and $W = 490.35\,N$ , then the force needed to keep the sled moving at a constant velocity is:

$F_{min,k} = 0.1\cdot (490.35\,N)$

$F_{min,k} = 49.035\,N$

A force of 49.035 newtons is needed to keep the sled moving at a constant velocity.

8 0

3 years ago

Which of the following body systems work together to get sells the oxygen they need to carry at the cellular respiration

djyliett [7]

The cells in your body help get oxygen to cellular respiration.

8 0

3 years ago