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3 years ago

What are some examples of how you have used, or could use, algebraic equations to solve problems in your everyday life?

1 answer:

6 0

Many of the most widely useful applications pertaining to equations involve the transfer of money. Such problems are often of the type “You have 25lbs packs of oranges, how much money do you have to pay if a pound of oranges cost $0.25”

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In the equation left parenthesis x squared plus 14 x right parenthesis plus left parenthesis y squared minus 18 y right parenthe

Phoenix [80]

Answer:

Complete the square on x by adding 49 to both sides.

Complete the square on y by adding 81 to both sides.

Step-by-step explanation:

We have been given an equation $(x^2+14x)+(y^2+18y)=5$ . We are asked to complete the squares for both x and y.

We know to complete a square, we add the half the square of coefficient of x or y term.

Upon looking at our given equation, we can see that coefficient of x is 14 and coefficient of y is 18.

$(\frac{14}{2})^2=7^2=49$

$(\frac{18}{2})^2=9^2=81$

Now, we will add 49 to complete the x term square and 81 to complete y term square on both sides of our given equation as:

$(x^2+14x+49)+(y^2+18y+81)=5+49+81$

Applying the perfect square formula $a^2+2ab+b^2=(a+b)^2$ , we will get:

$(x+7)^2+(y+9)^2=135$

Therefore, We can complete the square on x by adding 49 to both sides and the square on y by adding 81 to both sides.

7 0

2 years ago

378 times 6 with regrouping

jeka94

The answer is 2268 now you have to regroup it

5 0

3 years ago

Read 2 more answers

A manufacturing company measures the weight of boxes before shipping them to the customers. If the box weights have a population

NikAS [45]

Answer:

The probability that the average weight of the boxes will exceed 94 pounds is 43.25%

Step-by-step explanation:

1. Let's review the information provided to answer the question correctly:

Mean of the population of box weights = 90 pounds

Standard deviation of the population of box weights = 24 pounds

Sample size = 36 boxes

2. What is the probability that the average weight of the boxes will exceed 94 lb?

For answering this question, we will use the z-scores table.

For using the correct z-score, we should use the correct standard deviation. In this case, we have that:

94 - 90 = 4 pounds above the mean.

4 pounds are 4/24 of the standard deviation,

therefore, simplifying:

4/24 = 1/6 = 0.1666......and we'll round to 0.17

z-score is 0.17 because 4 pounds is 1/6 of the standard deviation (24).

The probability of a z-score is 0.5675, but in this case we're asked by a weight over 94 pounds, not under 94 pounds, thus:

1 - 0.5675 = 0.4325

The probability that the average weight of the boxes will exceed 94 pounds is 43.25%

8 0

2 years ago

Show your work.

Doss [256]

Answer:

1= 2,400 feet

2= 154 meters

3= 120 pints

4= 2. 056 centigrams

5= 16.1 C

6= 50F

7= -2.8C

1= multiply the length value by 3

2= divide the length value by 10

3= multiply the volume value by 8

4= divide the mass value by 10

5= Take the °F temperature and subtract 32. Multiply this number by 5. Divide this number by 9 to obtain your answer in °C.

6= multiply the temperature in degrees Celsius by 2, and then add 30 to get the (estimated) temperature in degrees Fahrenheit.

6 0

2 years ago

Read 2 more answers

Last week, the members of a weight loss support group collectively weighed 2,900 pounds. They just weighed in again and are now

Doss [256]

Answer:

2,784 lbs

Step-by-step explanation:

2900/100=29 (that is 1% of the 2900)

29*4=116 (that is 4% of 2900; how much weight they lost)

2900-116=2784 (current weight)

3 0

2 years ago