Answer:
y = 2x - 3
Step-by-step explanation:
We are asked to find the equation of a straight line
Step 1: find the slope
( 2 , 1) ( 5 , 7)
x_1 = 2
y_1 = 1
x_2 = 5
y_2 = 7
Insert the values into the equation
m = (y_2 - y_1 )/ (x_2 - x _1)
m = (7 - 1 )/ (5 - 2)
m = 6/3
= 2
Step 2: substitute m into the equation
y = mx + c
y = 2x + c
Step 3 : sub any of the two points given into the equation
Let's use ( 2, 1)
x = 2
y = 1
y = 2x + c.
1 = 2(2) + c
1 = 4 + c
c = 1 - 4
c = -3
Step 4: sub c into the equation
y = 2x + c
y = 2x - 3
(10x+5)4 = 30x + 3x + 6x +30
40x + 20 = 39x + 30
X = 10
perimeter of the square= 420
perimeter of the triangle= 420
64 inches is the correct answer. To get it you need to multiply the length times the width.
(this is incorrect. Sorry for the inconvenience)
if we look at the equation y = -2x - 1, is already in slope-intercept form, therefore, 
has a slope of -2.
now, parallel lines have exactly equal slopes, therefore a parallel to that one above, will have also a slope of -2, so we're really looking for a line whose slope is -2 and runs through -1, 7.
![\bf (\stackrel{x_1}{-1}~,~\stackrel{y_1}{7})\qquad \qquad \qquad slope = m\implies -2\\\\\\\stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-7=-2[x-(-1)]\\\\\\y-7=-2(x+1)\implies y-7=-2x-2\implies y=-2x+5](https://tex.z-dn.net/?f=%20%5Cbf%20%28%5Cstackrel%7Bx_1%7D%7B-1%7D~%2C~%5Cstackrel%7By_1%7D%7B7%7D%29%5Cqquad%20%5Cqquad%20%5Cqquad%20slope%20%3D%20%20m%5Cimplies%20-2%5C%5C%5C%5C%5C%5C%5Cstackrel%7B%5Ctextit%7Bpoint-slope%20form%7D%7D%7By-%20y_1%3D%20m%28x-%20x_1%29%7D%5Cimplies%20y-7%3D-2%5Bx-%28-1%29%5D%5C%5C%5C%5C%5C%5Cy-7%3D-2%28x%2B1%29%5Cimplies%20y-7%3D-2x-2%5Cimplies%20y%3D-2x%2B5%20)
