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Elodia [21]
3 years ago
15

If the right-hand side of a quadratic equation does not equal zero, you need to ______ the number or expression on the right-han

d side from both sides before you can use the quadratic formula.
Mathematics
2 answers:
maxonik [38]3 years ago
8 0

We have two cases here:

Case 1:

If we have a quadratic equation of the form:

ax^{2} +bx = c

Now if we need to bring c to the left side , we will have to subtract it from left side.

ax^{2} +bx- c=0

Case 2:

we have a quadratic equation of the form:

ax^{2} +bx = -c

Now if we need to bring c to the left side , we will have to add it on the left side.

ax^{2} +bx+c=0

Answer : If the right-hand side of a quadratic equation does not equal zero, you need to either add or subtract the number or expression on the right-hand side from both sides before you can use the quadratic formula.

timama [110]3 years ago
7 0
If the right hand side of a quadratic equation does not equal zero, you need to subtract the number...
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Simplify.<br> [72/(-9)]/(-1/3)
Nutka1998 [239]

Answer:

24

Step-by-step explanation:

(72/-9) / (-1/3)

72/-9) x (-3/1)

(72)*(-3) = - 216/ -9

= 24

4 0
3 years ago
OLLEGE
Sophie [7]

<u>Part 1</u>

<u />(f\circ g)(x)=f(\sqrt{x})=4\sqrt{x}+1

We need to make sure the radical is defined, meaning the radicand has to be non-negative. Thus, the domain is \boxed{[0, \infty)}

<u>Part 2</u>

<u />(g \circ f)(x)=g(4x+1)=\sqrt{4x+1}

We need to make sure the radical is defined, meaning the radicand has to be non-negative. Thus,

4x+1 \geq 0\\\\4x \geq -1\\\\x \geq -\frac{1}{4}

Thus, the domain in interval notation is \boxed{\left[-\frac{1}{4}, \infty)}

8 0
2 years ago
In a recent survey, 60% of the community favored building a health center in their neighborhood. If 14 citizens are chosen, find
andreev551 [17]

Answer:

Probability that exactly 5 of them favor the building of the health center is 0.0408.

Step-by-step explanation:

We are given that in a recent survey, 60% of the community favored building a health center in their neighborhood.

Also, 14 citizens are chosen.

The above situation can be represented through Binomial distribution;

P(X=r) = \binom{n}{r}p^{r} (1-p)^{n-r} ; x = 0,1,2,3,.....

where, n = number of trials (samples) taken = 14 citizens

         r = number of success = exactly 5

        p = probability of success which in our question is % of the community

              favored building a health center in their neighborhood, i.e; 60%

<em>LET X = Number of citizens who favored building of the health center.</em>

So, it means X ~ Binom(n=14, p=0.60)

Now, Probability that exactly 5 of them favor the building of the health center is given by = P(X = 5)

        P(X = 5) = \binom{14}{5} \times 0.60^{5} \times (1-0.60)^{14-5}

                      = 2002 \times 0.60^{5} \times 0.40^{9}

                      = 0.0408

Therefore, Probability that exactly 5 of them favor the building of the health center is 0.0408.

4 0
3 years ago
Danny had a bag of cheese puffs before he ate 14 puffs there were 122 puffs in the bag his mouth m said he has to split the rest
marissa [1.9K]
122-14 = 108
108÷3 = 36
Your answer is 36
5 0
3 years ago
A bag contains counters that are red, black , or green . 1/3 of the counters are red 1/6 of the counters are black There are 15
Nadya [2.5K]

Answer:

There are 5 black counters in the bag.

Step-by-step explanation:

15 green counters in the bag

The proportion of green counters is given by:

p = 1 - (\frac{1}{3} + \frac{1}{6}) = 1 - (\frac{2}{6}+\frac{1}{6}) = 1 - \frac{3}{6} = 1 - \frac{1}{2} = \frac{2}{2} - \frac{1}{2} = \frac{1}{2}

So, we have that, the total is x. So

\frac{x}{2} = 15

x = 30

There are 30 total counters.

How many black counters are in the bag ?

A sixth of the counters are black. So

\frac{1}{6} \times 30 = \frac{30}{6} = 5

There are 5 black counters in the bag.

8 0
3 years ago
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