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horrorfan [7]
3 years ago
5

Opal can make 9 beaded bracelets per hour, and Lynette can make 6 per hour. Together how many hours should it take them to make

45 beaded bracelets?
Mathematics
1 answer:
marin [14]3 years ago
4 0

Answer:

I'm pretty sure it is 3 hours.

Step-by-step explanation:

Well, when you add 9 plus 6, you get 15. Then you divie 45 by 15, which gives you three. Hope this helps. Good luck :D

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Angle A is circumscribed about circle O. What is the measure of A.
wlad13 [49]

Answer:

88

Step-by-step explanation:

Sum of angles in a quadrilateral= 360 degrees

<OCA=90degrees [ tangent perpendicular to the circle.

<OBA= 90degrees =tangent perpendicular

to the circle

<OCA + <OBA +92 + <OAB= 360

90 + 90 + 92 + <OAB = 360

272 + < OAB = 360

<0AB= 360- 272 =88 degrees

5 0
3 years ago
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4 years ago
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Mila [183]
Step One
======
Find the length of FO (see below)

All of the triangles are equilateral triangles. Label the center as O
FO = FE = sqrt(5) + sqrt(2)

Step Two
======
Drop a perpendicular bisector from O to the midpoint of FE. Label the midpoint as J. Find OJ

Sure the Pythagorean Theorem. Remember that OJ is a perpendicular bisector.

FO^2 = FJ^2 + OJ^2
FO = sqrt(5) + sqrt(2)
FJ = 1/2 [(sqrt(5) + sqrt(2)]                                           \
OJ = ??

[Sqrt(5) + sqrt(2)]^2 = [1/2(sqrt(5) + sqrt(2) ] ^2 + OJ^2
5 + 2 + 2*sqrt(10) = [1/4 (5 + 2 + 2*sqrt(10) + OJ^2
7 + 2sqrt(10) = 1/4 (7 + 2sqrt(10)) + OJ^2      Multiply through by 4
28 + 8* sqrt(10) = 7 + 2sqrt(10) + 4 OJ^2    Subtract 7 + 2sqrt From both sides
21 + 6 sqrt(10) = 4OJ^2   Divide both sides by 4
21/4 + 6/4* sqrt(10) = OJ^2
21/4 + 3/2 * sqrt(10) = OJ^2 Take the square root of both sides.
sqrt OJ^2 = sqrt(21/4 + 3/2 sqrt(10) )
OJ = sqrt(21/4 + 3/2 sqrt(10) )

Step three
find h
h = 2 * OJ
h = 2* sqrt(21/4 + 3/2 sqrt(10) ) <<<<<< answer.


7 0
3 years ago
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Iteru [2.4K]

Answer:

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