Answer:
The value of the Golden Igloo is $227.4 million.
Explanation:
First, we need to find the inner and the outer volume of the half-spherical shell:
The total volume is given by:
Where:
: is the inner volume
: is the inner radius = 1.25/2 = 0.625 m
: is the outer volume
: is the outer radius = 1.45/2 = 0.725 m
Then, the total volume of the Igloo is:
![V_{T} = \frac{2}{3}\pi r_{o}^{3} - \frac{2}{3}\pi r_{i}^{3} = \frac{2}{3}\pi [(0.725 m)^{3} - (0.625 m)^{3}] = 0.29 m^{3}](https://tex.z-dn.net/?f=%20V_%7BT%7D%20%3D%20%5Cfrac%7B2%7D%7B3%7D%5Cpi%20r_%7Bo%7D%5E%7B3%7D%20-%20%5Cfrac%7B2%7D%7B3%7D%5Cpi%20r_%7Bi%7D%5E%7B3%7D%20%3D%20%5Cfrac%7B2%7D%7B3%7D%5Cpi%20%5B%280.725%20m%29%5E%7B3%7D%20-%20%280.625%20m%29%5E%7B3%7D%5D%20%3D%200.29%20m%5E%7B3%7D%20)
Now, by using the density we can find the mass of the Igloo:
Finally, the value (V) of the antiquity is:
Therefore, the value of the Golden Igloo is $227.4 million.
I hope it helps you!
Hey there!:
Isotopes : abundance :
46 Ti 8.0%
47 Ti 7.8 %
48 Ti 73.4 %
49 Ti 5.5 %
50 Ti 5.3 %
Weighted average = ∑ Wa * % / 100
Therefore:
( 46 * 8.0) + (47 * 7.8 ) + (48 * 73.4 ) + ( 49 * 5.5 ) + ( 50*5.3 ) / 100 =
4792.3 / 100
= 47.923 a.m.u
Hope that helps!
I'm not sure how many sign fig's you are required to have.
However I think the final answer would be 0.05 Moles, because of the .5g, that is considered 1 sign fig.
Answer: Calories
Explanation: One calorie is the amount of energy required to raise one gram of water one degree Celsius
The answer is -11.2 fahrenheit.
