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Aneli [31]
3 years ago
11

Both pyrrole and pyridine are aromatic compounds, and undergo electrophilic aromatic substitution (EAS). Using a resonance argum

ent, predict the regiochemistry of EAS on both pyrrole and pyridine. As part of your argument, you must draw resonance structures for the arenium ion leading to each possible regiochemistry, and compare the stabilities of the resonance hybrids. In addition, make a reasoned statement about whether you think each one would react faster or slower than benzene and why.

Chemistry
1 answer:
soldi70 [24.7K]3 years ago
5 0

Answer:

See attached picture for both electrophillic substitution in pyrole and in pyridine.

Explanation:

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Dierdra began writing a summary of the relationship between the first and second laws of thermodynamics.
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the correct answer is B

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2 years ago
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You have a glass of pure water and add acidic lemon juice to it. This means that you are adding _____ to it, and the solution wi
mr Goodwill [35]

Answer: acid; acidic

Explanation:

You have a glass of pure water and add acidic lemon juice to it. This means that you are adding ACID to it, and the solution will become ACIDIC.

Pure water has a pH value of 7

Lemon juice has a pH value less than 7 i.e acidic

Therefore, addition of lemon juice to pure water will drop the latter pH from 7 to form a final solution that is ACIDIC.

8 0
3 years ago
If there is no net force acting on an object, the object will
Sonbull [250]
The answer is c , it cant change a speed or a motion if it doesnt have a net force acting on it
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3 years ago
What is the molecular formula of the product formed from the oxidation of 2-methyl-2,3-pentandiol with Jones reagent (CrO3, H ,
ExtremeBDS [4]

Answer:

C6H12O2

Explanation:

The Jones reagent is a reagent in organic chemistry used to convert primary alcohols to carboxylic acids and secondary alcohols to ketones. Recall that tertiary alcohols can not be oxidized.

The compound  2-methyl-2,3-pentandiol contains one secondary and one tertiary alcohol. The secondary alcohol is oxidized to a ketone while the tertiary alcohol is not oxidized.

Hence the product of the oxidation using Jones reagent is 2-Hydroxy-2-methyl-3-pentanone with the molecular formula C6H12O2.

7 0
2 years ago
A mixture of 0.439 M H 2 , 0.317 M I 2 , and 0.877 M HI is enclosed in a vessel and heated to 430 °C. H 2 ( g ) + I 2 ( g ) − ⇀
n200080 [17]

Answer : The concentration of H_2,I_2\text{ and }HI at equilibrium is, 0.244 M, 0.122 M and 1.267 M respectively.

Explanation :

The given chemical reaction is:

                             H_2(g)+I_2(g)\rightarrow 2HI(g)

Initial conc.       0.439      0.317       0.877

At eqm.          (0.439-x)    (0.317-x)  (0.877+2x)

As we are given:

K_c=54.3

The expression for equilibrium constant is:

K=\frac{[HI]^2}{[H_2][I_2]}

Now put all the given values in this expression, we get:

54.3=\frac{(0.877+2x)^2}{(0.439-x)\times (0.317-x)}

x = 0.195 and x = 0.690

We are neglecting the value of x = 0.690 because equilibrium concentration can not be more than initial concentration.

Thus, the value of x = 0.195 M

The concentration of H_2 at equilibrium = (0.439-x) = (0.439-0.195) = 0.244 M

The concentration of I_2 at equilibrium = (0.317-x) = (0.317-0.195) = 0.122 M

The concentration of HI at equilibrium = (0.877+2x) = (0.877+2\times 0.195) = 1.267 M

3 0
3 years ago
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