Answer:
% Mass of sand = 35.95%
% Mass of KBr = 64.05%
Explanation:
From the question given, we obtained the following:
Mass of mixture( KBr + sand) = 10g
Mass of sand = 3.595g
Mass of KBr = 10 — 3.595 = 6.405g
% Mass of sand = ( Mass of sand / mass of mixture) x 100
% Mass of sand = (3.595 / 10) x100
% Mass of sand = 35.95%
We can obtain the percentage of KBr by subtracting the percentage of sand from 100. This is illustrated below:
% Mass of KBr = 100 — 35.95
% Mass of KBr = 64.05%
2.15 x 10⁻³mL
Explanation:
Given parameter:
Volume of blood sample in uL = 2.15uL
Conversion uL → mL
micro- and milli- are both prefixes of sub-units.
liter is a unit of volume of a substance.
micro - is 10⁻⁶
milli- is of the order 10⁻³
The problem is converting from micro to milli:
if we multiply 10⁻⁶ by 10³ we would have our milli;
1000uL = 1mL
2.15uL : 2.15uL x 
= 2.15 x 10⁻³mL
learn more:
Volume brainly.com/question/5055270
#learnwithBrainly
Explanation:
Fe. O
72.40/ 56 27.60/16
____________________
1.29/1.29 1.725/1.29
_____________________
1. :. 1
<h3>Emperical formula = FeO</h3>
