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Masteriza [31]
3 years ago
13

GivenL C2H2 + 5O2 ------> 4 CO2 + 2H2O

Chemistry
1 answer:
diamong [38]3 years ago
7 0

Answer:

101 L

Explanation:

35.0 g KOH ÷ 56.09 g/mol KOH × (1 mol H2O/ 1 mol KOH) × 18 g/mol H2O = 11.2 g H2O

35.0 g HCl ÷ 36.45 g/mol HCl × (1 mol H2O/ 1 mol HCl) × 18 g/mol H2O = 17.3 g H2O

35.0 g KOH is the limiting reactant

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Answer:

B

Explanation:

Firstly, we will need to calculate the number of moles. To do this, we make use of the ideal gas equation

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P = 780mmHg, we convert this to pascal.

760mHG = 101325pa

780mmHg = xpa

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V= 400ml = 0.4L

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Substituting these values into the equation yields the following:

n = (103991 * 0.4)/(8314.463 * 408.15)

= 0.012 moles

Now we know 1 mole contains 6.02 * 10^23 molecules, hence, 0.012moles will contain = 0.012 * 6.02 * 10^23 = 7.38 * 10^21 molecules

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3 years ago
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Explanation:

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Natali5045456 [20]
Thank you for the points

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