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Deffense [45]
3 years ago
7

Are our current copyright policies helping society or hurting society? i need help

Computers and Technology
1 answer:
Oksanka [162]3 years ago
5 0

Answer:

helping society

Explanation:

it can help you to protect your works and creativity and brilliant ideas from liars and cheaters and frauds

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How does a Graphical User Interface (GUI) interact with a desktop or laptop computer?
Viefleur [7K]

Windows, icons, menus, and pointers does  a  graphical  user interface (GUI) interact with a  desktop or laptop computer.

  • Windows, icons, menus, and pointers

<u>Explanation:</u>

Graphics user interface (gui) made a big resolution on desktop or laptop or tablet or workstation industries. In olden days till  1994 still, people were using the black and white computer where a desktop consists of keyboard and printer and monitors where display color white and black.

If we open a picture it will display only in black and white so games are in black and white mode. After windows  3.1  we have seen color picture and mouse interface is used. Since technology developed and interface in GUI is also developed improved in windows icon menu and mouse pointer.

As technology developed we going back to a dark mode such as black and white mode.

4 0
4 years ago
I have a real struggle when it comes to working with strings, whether they're arrays or pointers to strings, and I'm lost cause
neonofarm [45]
In C, you deal with a string always via a pointer. The pointer by itself will not allocate memory for you, so you'll have to take care of that.

When you write char* s = "Hello world"; s will point to a "Hello world" buffer compiled into your code, called a string literal.

If you want to make a copy of that string, you'll have to provide a buffer, either through a char array or a malloc'ed bit of memory:

char myCopy[100];
strcpy(myCopy, s);

or 

char *myCopy;
myCopy = (char*)malloc( strlen(s) + 1 );
strcpy(myCopy, s);

The malloc'ed memory will have to be returned to the runtime at some point, otherwise you have a memory leak. The char array will live on the stack, and will be automatically discarded.

Not sure what else to write here to help you...
6 0
3 years ago
Select the correct text in the n passage.
finlep [7]

The correct text in the passage that defines the matting process is it provides a decorative edge to the print and includes a mechanism to hang the photo.

<h3>What is matting in compositing?</h3>

The  Matting and compositing are known to be some key operations in graphics.

In the matting process, a background element that has arbitrary shape is known to be extracted from a background image.

Hence, The correct text in the passage that defines the matting process is it provides a decorative edge to the print and includes a mechanism to hang the photo.

Learn more about Matting from

brainly.com/question/26875233

#SPJ1

8 0
1 year ago
In the Scrum board, prioritizing the issue backlog is done in the ———- mode.
IrinaK [193]

Answer:

The answer to this question is given below in the explanation section

Explanation:

Scrum Board is a tool that is used by the scrum teams to view the product backlog. The Scrum task board makes the sprint backlog visible for the team.

In the Scrum board, prioritizing the issue backlog is done in the <u>Current View</u> mode.

However, it is noted that in Scrum board there are two view modes (Tree view mode and List view mode) for the issues in the backlog. The issues that are prioritized is listed in the current view mode.  

7 0
3 years ago
Give a big-O estimate for the number of operations,
Kazeer [188]

Answer:

Explanation:

For the first iteration of i for loop 1 to n, the j for loop will run from 2 to n times. i.e. n-1 times.

For the second iteration of i for loop, the j for loop will run from 3 to n times. i.e. n-2 times.

From the third to the last iteration of i for loop, the j for loop will run n-1 to n times. i.e. 2 times.

From the second to the last iteration of i for loop, the j for loop will run from n to n times. i.e. 1 time.

For the last iteration of i for loop, the j for loop will run 0 times because i+1 >n.

Hence the equation looks like below:

1 + 2 + 3 + ...... + (n-2) + (n-1) = n(n-1)/2

So the number of total iterations is n(n-1)/2.

There are two operations per loop, i.e. Comparison and Multiplication, so the iteration is 2 * n(n-1)/2 = n ^2 - n

So f(n) = n ^ 2 - n

f(n) <= n ^ 2 for n > 1

Hence, The algorithm is O(n^2) with C = 1 and k = 1.

6 0
4 years ago
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