Please help ASAP! Will Mark BRAINLIEST! AND 10 POINTS IF ANSWERED CORRECTLY!

Mathematics

1 answer:

Reil [10]3 years ago

5 0

D because the total was 40.25

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Use the explicit formula an=a1+(n-1)•d to find the 300th term of the sequence below 57,66,75,84,93

Grace [21]

$a_{300}=57+(300-1)\cdot9\\
a_{300}=57+299\cdot9\\
a_{300}=57+2691\\
a_{300}=2748$

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3 years ago

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Can help me how<br>Macam mana...

Alborosie

Step-by-step explanation:

2(x+2)=7

2x+4=7

2x=7-4

2x=3

x=3/2

ii)3x + y =8 , y=x

3x + x = 8

4x = 8

x = 2

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3 years ago

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Suppose you have $10,000 to invest. Which of the two rates would yield the larger amount in 4 years. 7% compounded quarterly or

GalinKa [24]

$K=\$10,000\ \ \ and\ \ \ Sum=K\cdot(1+ \frac{p}{100})^n\\----------------------- \\1)\ \ \ 7\%\ quarterly\\\\ \ \Rightarrow\ \ \frac{1}{4} \cdot7\% =1.75\%\ \ annually\ \ \Rightarrow\ \ p=1.75\\\\ quarterly\ \Rightarrow\ \ 4\ times\ annually\ \Rightarrow\ \ 16\ times\ in\ 4\ years\ \Rightarrow\ \ n=16\\\\Sum(7\%)=\$10,000\cdot(1+ \frac{1.75}{100})^{16}=\\ \\.\ \ \ \ \ \ \ \ \ \ \ \ =\$10,000\cdot(1+0,0175)^{16}\approx\$13199.29\\------------------------\\$

$2)\ \ \ 6.94\%\ daily\\\\ \ \Rightarrow\ \ \frac{1}{365} \cdot6.94\% \approx0.019\%\ \ annually\ \ \Rightarrow\ \ p=0.019\\\\ daily\ \Rightarrow\ 365\ times\ annually\ \Rightarrow\ 1420\ times\ in\ 4\ years\ \Rightarrow\ n=1420\\\\Sum(6.94\%)=\$10,000\cdot(1+ \frac{0.019}{100})^{1420}=\\ \\.\ \ \ \ \ \ \ \ \ \ \ \ =\$10,000\cdot(1+0,00019)^{1420}\approx\$13096.69\\---------------------------\\\$13,199.29 > \$13,096.69\\\\Ans.\ the\ larger\ amount\ gives\ the\ compounded\ quarterly.$

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3 years ago

Make a stem-and-leaf plot for the following data. 59, 38, 33, 26, 44, 35, 32, 47, 45, 24, 27, 46, 34, 30, 36

aliina [53]

Stem : leaf :
2 4,6,7
3 0,2,3,4,5,6,8
4 4,5,6,7
5 9

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3 years ago

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Tom predicted that the Giants would score three 3-point field goals, score two 6-point touchdowns, and score 1 extra point. If T

Bingel [31]

3*3 = 9

2*6 = 12

1*1 = 1

9+12+1 = 22

The Giants would score 22 points if Tom is correct

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3 years ago

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