The other person
is right
24= 3*2^3
88= 11*2^3
664= 83*2^3 -> 83=11+72 = 11 + 2^3*3^2
664=2^3 (11+2^3*3^2) = 88 +(2^3*2^3*3^2) = 88 +(24^2)
8408= 1051 * 2^3 -> 1051= 83+968 -> 968 = 2^3 * 11^2
8408= 2^3 (83+2^3*11^2) = 664 +(2^3*2^3*11^2) = 664 +(88^2)
So:
a(n) = a(n-1) + a(n-2)^2
Lets check: 88+24^2= 664
664+88^2= 8408
There are no given coordinates, so it's impossible to answer your question. I'm sorry.
Answer:
H0: p ≤ 0.50
Ha: p > 0.50
Step-by-step explanation:
The null hypothesis (H0) tries to show that no significant variation exists between variables or that a single variable is no different than its mean. While an alternative Hypothesis (Ha) attempt to prove that a new theory is true rather than the old one. That a variable is significantly different from the mean.
For the case above;
Let p represent the proportion of households in the city that gave a charitable donation in the past year
The null hypothesis is that the proportion of households in the city that gave a charitable donation in the past year is not more that 0.50
H0: p ≤ 0.50
The alternative hypothesis is that the proportion of households in the city that gave a charitable donation in the past year is more that 0.50
Ha: p > 0.50
