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pogonyaev
3 years ago
15

Please help do not guess please

Mathematics
1 answer:
Alex Ar [27]3 years ago
8 0

Answer:

2x-3 = -11

Step-by-step explanation:

|2x-3| = 11

by definition of absolute numbers,

2x-3 = 11 (given)

or

2x-3 = -11 (answer)

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2 years ago
A large rectangle has length a + b and width c + d. Therefore, its area is (a + b)(c + d).
melamori03 [73]

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6 0
3 years ago
Simplify 4x+2 - x^2 +x-12 / x-3<br><br> a) 3x-2<br> b)3x+4<br> c)5x-4<br> d)5x+4
Ostrovityanka [42]
Hello

The asnwer is C.

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3 0
3 years ago
Read 2 more answers
A recent study asked U. S. Adults to name 10 historic events that occurred during their lifetime that have had the greatest impa
Nadusha1986 [10]

Using the z-distribution, as we are working with a proportion, it is found that the 99% confidence interval for the proportion of all U. S. Adults who would include the 9/11 attacks on their list of 10 historic events is (0.7458, 0.7942). It means that we are 99% sure that the true proportion for all U.S. adults is between these two bounds.

<h3>What is a confidence interval of proportions?</h3>

A confidence interval of proportions is given by:

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which:

  • \pi is the sample proportion.
  • z is the critical value.
  • n is the sample size.

In this problem, the parameters are:

z = 2.575, n = 2000, \pi = 0.77

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.77 - 2.575\sqrt{\frac{0.77(0.23)}{2000}} = 0.7458

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.77 + 2.575\sqrt{\frac{0.77(0.23)}{2000}} = 0.7942

The 99% confidence interval for the proportion of all U. S. Adults who would include the 9/11 attacks on their list of 10 historic events is (0.7458, 0.7942). It means that we are 99% sure that the true proportion for all U.S. adults is between these two bounds.

More can be learned about the z-distribution at brainly.com/question/25890103

7 0
2 years ago
Can you answer this Algebra question please?<br> (Just A, thank you).
Eduardwww [97]

d_f=d_i+v_0t+\dfrac{1}{2}at^2 \\d_f-d_i-\dfrac{1}{2}at^2=v_0t \\v_0=\boxed{\dfrac{d_f+d_i-\frac{1}{2}at^2}{t}} \\

Hope this helps.

8 0
2 years ago
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