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3 years ago

ms. young is 25 years old. her grandfather is 4 times as old. how old is her grandfather? use place value or standard algorithm

Mathematics

2 answers:

Delicious77 [7]3 years ago

8 0

Answer:

he is 100 yrs old.

Step-by-step explanation:

25x4=100

olga_2 [115]3 years ago

7 0

Answer:

Her grandfather is 100 years old.

Step-by-step explanation:

[work in picture, it says 90 instead of 100]

Ms. young is 25 years old. Her grandpa is 4 times older.

25 * 4 = 100

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Can anyone please help me -1.6 = k + 0.9

ololo11 [35]

Answer: k=-6

-6=k+0

Step-by-step explanation:

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3 years ago

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A circle has the equation 2x²+12x+2y²−16y−150=0.

KonstantinChe [14]

Answer: B. The coordinates of the center are (-3,4), and the length of the radius is 10 units.

Step-by-step explanation:

The equation of a circle in the center-radius form is:

$(x-h)^{2} +(y-k)^{2}=r^{2}$ (1)

Where $(h,k)$ are the coordinates of the center and $r$ is the radius.

Now, we are given the equation of this circle as follows:

$2x^{2}+12x+2y^{2}-16y-150=0$ (2)

And we have to write it in the format of equation (1). So, let's begin by applying common factor 2 in the left side of the equation:

$2(x^{2}+6x+y^{2}-8y-75)=0$ (3)

Rearranging the equation:

$x^{2}+6x+y^{2}-8y=75$ (4)

$(x^{2}+6x)+(y^{2}-8y)=75$ (5)

Now we have to complete the square in both parenthesis, in order to have a perfect square trinomial in the form of $(a\pm b)^{2}=a^{2}\pm+2ab+b^{2}$ :

For the first parenthesis:

$x^{2}+6x+b^{2}$

We can rewrite this as:

$x^{2}+2(3)x+b^{2}$

Hence in this case $b=3$ and $b^{2}=9$ :

$x^{2}+2(3)x+3^{2}=x^{2}+6x+9=(x+3)^{2}$

For the second parenthesis:

$y^{2}-8y+b^{2}$

We can rewrite this as:

$y^{2}-2(4)y+b^{2}$

Hence in this case $b=-3$ and $b^{2}=9$ :

$y^{2}-2(4)y+4^{2}=y^{2}-8y+16=(y-4)^{2}$

Then, equation (5) is rewritten as follows:

$(x^{2}+6x+9)+(y^{2}-8y+16)=75+9+16$ (6)

Note we are adding 9 and 16 in both sides of the equation in order to keep the equality.

Rearranging:

$(x-3)^{2}+(y-4)^{2}=100$ (7)

At this point we have the circle equation in the center radius form $(x-h)^{2} +(y-k)^{2}=r^{2}$

Hence:

$h=-3$

$k=4$

$r=\sqrt{100}=10$

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4 years ago

A team t-shirt costs $3 per adult and $2 per child. On a certain day, the total number of adults (a) and children (c) who bought

lesya [120]

A+c=100

3a+2c=275, from the first c=100-a making the 2nd equation become:

3a+2(100-a)=275 perform indicated multiplication on left side

3a+200-2a=275 combine like terms on left side

a+200=275, subtract 200 from both sides

a=75, and since c=100-a

c=100=75=25

So the answer is D. 25 children and 75 adults
Equation 1: a+c=100
Equation 2: 3a+2c=275

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3 years ago

Given a≠±b and a^2−b^2 / a+b =12, find a−b. pls hlep

Readme [11.4K]

Answer:

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Step-by-step explanation:

Given

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a² - b² = (a - b)(a + b)

Thus

$\frac{(a-b)(a+b)}{a+b}$ = 12

Cancel the common factor (a + b) on numerator/ denominator, thus

a - b = 12

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Tpy6a [65]

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Step-by-step explanation:

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