I'm not sure but I had it then I forgot
Answer:
1.8m^2 approx
Step-by-step explanation:
Given data
P1= 1400N
A1=0.5m^2
P2=5000 N
A2=??
Let us apply the formula to calculate the Area A2
P1/A1= P2/A2
substitute
1400/0.5= 5000/A2
cross multiply
1400*A2= 5000*0.5
1400*A2= 2500
A2= 2500/1400
A2= 1.78
Hence the Area is 1.8m^2 approx
Does this help you at all?
The hyperbolic cos (cosh) is given by
cosh (x) = (e^x + e^-x) / 2
The slope of a tangent line to a function at a point is given by the derivative of that function at that point.
d/dx [cosh(x)] = d/dx[(e^x + e^-x) / 2] = (e^x - e^-x) / 2 = sinh(x)
Given that the slope is 2, thus
sinh(x) = 2
x = sinh^-1 (2) = 1.444
Therefore, the curve of y = cosh(x) has a slope of 2 at point x = 1.44
Answer:
z = 15/30 = 3/6
Step-by-step explanation:
1/5z - 5/6 = - 4/5z - 1/3
1/5z + 4/5z = - 1/3 + 5/6
5/5z = - 2/6 + 5/6
5/5z = 3/6
z = 3/6 / 5/5
z = 3/6 * 5/5
z = 15/30
