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Ivenika [448]
3 years ago
11

Create The equation used to find the magnitude of the vector v represented by

Mathematics
1 answer:
lbvjy [14]3 years ago
6 0

The magnitude can be found by using the PythaGORAS THEOREM:-

PQ =  √[ (-3 - (-5))^2 + (4 - 2)^2 ]


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Find the distance between the points A(2,-1) and B(-4, 2). (simplify your answer)
Pani-rosa [81]

Answer:

d = 3\sqrt{5}

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Algebra II</u>

  • Distance Formula: d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Step-by-step explanation:

<u>Step 1: Define</u>

Point A (2, -1)

Point B (-4, 2)

<u>Step 2: Find distance </u><em><u>d</u></em>

Simply plug in the 2 coordinates into the distance formula to find distance <em>d</em>.

  1. Substitute [DF]:                    d = \sqrt{(-4-2)^2+(2+1)^2}
  2. Subtract/Add:                       d = \sqrt{(-6)^2+(3)^2}
  3. Exponents:                           d = \sqrt{36+9}
  4. Add:                                      d = \sqrt{45}
  5. Simplify:                               d = 3\sqrt{5}
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How to find distance of a horizontal line on the cordinate plane
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Expand (3X-4)2 and write in standard form
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If you mean (3x-4)^2, the answer will be 9x^2 - 24x + 16.
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Which are the roots of the quadratic function f(q) = q2 – 125? Select two options.
Assoli18 [71]

Answer:

±11.18

Step-by-step explanation:

the function is:

f(q)=q^2-125

and to find the roots we need to find which values of q makes the function result in zero:

q^2-125=0

solving for q:

q^2=125\\q=\sqrt{125}

A square root has two solutions, one positive and one negative, so the solutions are:

q=±\sqrt{125} ≈ ±11.18

the roots of the quadratic equation are +11.18 and -11.18

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A high school math class has 28 students: 18 seniors and 10 juniors. What is the probability that four randomly selected student
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Answer:

64

Step-by-step explanation:

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